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2 years ago

The HCF of 36 72 63The LCM of 8 9 12

Mathematics

1 answer:

MakcuM [25]2 years ago

7 0

LCM of 8,9,12 is 72

HCF of 36 72 63 is 3

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Simplify these expressions a) 5x +3x + 2y + 4y b) 6x - 2x + 8y - 6y

cestrela7 [59]

Answer:

$a) \: 5x + 3x + 2y + 4y \\ = 8x + 6y$

$b) \: 6x - 2x + 8y - 6y \\ = 4x + 2y$

I hope I helped you^_^

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2 years ago

Sean Matthews is a waiter at the Duluxe Lounge. In his first weekly pay in March, he earned $300.00 for the 40 hours he worked.

Gnoma [55]

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2 years ago

A tire company finds that the lifespan for one brand of its tires is normally distributed with a mean of 47,500 miles and a stan

Illusion [34]

Answer:

42580 miles

Step-by-step explanation:

Mean = $\mu = 47500$

$\sigma = 3000$

The manufacturer does not want to replace more than 5% of the tires

$P(X\leq x)=5\%$

$P(\frac{x-\mu}{\sigma}\leq \frac{x-47500}{3000})=0.05$

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Hence the approximate number of miles for the warranty is 42580 miles

6 0

3 years ago

The largest 4 digit number exactly divisible by 88 is: a.9944 b.9768 c.9988 d.8888

serious [3.7K]

Answer:

Step-by-step explanation:

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2 years ago

Consider three events A, B and C with following properties.

lisov135 [29]

By the inclusion/exclusion principle,

$\mathbb P(D)=\mathbb P(A\cup B\cup C)$
$\mathbb P(D)=\mathbb P(A)+\mathbb P(B)+\mathbb P(C)-\bigg(\mathbb P(A\cap B)+\mathbb P(A\cap C)+\mathbb P(B\cap C)\bigg)+\mathbb P(A\cap B\cap C)$
$\mathbb P(D)=\dfrac14+\dfrac16+\dfrac14-\dfrac39+\dfrac1{13}$
$\mathbb P(D)=\dfrac{16}{39}\neq1$

So the union of A, B, and C does not constitute the entire sample space.

5 0

3 years ago

The HCF of 36 72 63The LCM of 8 9 12​

The HCF of 36 72 63The LCM of 8 9 12