Question

Question 2 of 10 What is the length of side s of the square shown below? 45 6 09 90° O A. 6 O B. 2 O C. 32 O D. 5 O E. 3 OF. 6-12​

Answer 1

Answer:

C

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos45° = $\frac{\sqrt{2} }{2}$ , then

cos45° = $\frac{adjacent}{hypotenuse}$ = $\frac{s}{6}$ = $\frac{\sqrt{2} }{2}$ ( cross- multiply )

2s = 6$\sqrt{2}$  ( divide both sides by 2 )

s = 3$\sqrt{2}$ → C