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irina1246 [14]
3 years ago
13

A ball is thrown into the air with an initial velocity of 22 meters per second.

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

27.4 metres

Step-by-step explanation:

Um, your question is missing the x's. I'm going to assume, -4.9x^2+22x+5.5

= -4.9(3)^2+22(3)+5.5

= 27.4

At 3 seconds the ball is 27.4 metres above the ground.

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Answer:

x = 0

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Step-by-step explanation:

3x + 9y = 18 ---------eqn 1

y = x + 2---------eqn 2

Substitute eqn 2 into eqn 1, for the value of y

3x + 9( x + 2) = 18

3x + 9x + 18 = 18

12x + 18 = 18

12x = 18 -18

12x = 0

Divide both sides by 12 , to get the value of x.

12x/ 12 = 0/12

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Substitute x = 0 into eqn 2

y = x + 2

y = 0 +2

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Hint: to confirm the values

x = 0

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Let's take eqn 1 ,

3x + 9y = 18

3(0) + 9(2)

= 0 + 18

= 18

Correct

Let's take eqn 2

y = x + 2

Let's find y

y = 0 + 2

y = 2

Correct too

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