A ball is thrown into the air with an initial velocity of 22 meters per second.
1 answer:
Answer:
27.4 metres
Step-by-step explanation:
Um, your question is missing the x's. I'm going to assume, -4.9x^2+22x+5.5
= -4.9(3)^2+22(3)+5.5
= 27.4
At 3 seconds the ball is 27.4 metres above the ground.
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