Question

A ball is thrown into the air with an initial velocity of 22 meters per second.

Answer 1

Answer:

27.4 metres

Step-by-step explanation:

Um, your question is missing the x's. I'm going to assume, -4.9x^2+22x+5.5

= -4.9(3)^2+22(3)+5.5

= 27.4

At 3 seconds the ball is 27.4 metres above the ground.