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natka813 [3]
3 years ago
7

Four points are always coplanar if: Check all that apply. A. all of them are collinear B. they are not in the same plane. C. thr

ee of them are coplanar. D. they lie in the same plane. which one is it?​
Mathematics
1 answer:
pentagon [3]3 years ago
7 0

They are collinear

they lie in the same plane

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simply combining like teams 3a-2b-ab-(a-b+ab)-4ab+2b-a if l write tge answers as 1a- 6ab is it correct ?​
Semenov [28]

Answer:

-6 a b + b + a

Step-by-step explanation:

Simplify the following:

-(a - b + a b) - a b - 4 a b + 2 b - 2 b + 3 a - a

Hint: | Group like terms in 3 a - 2 b - a b - (a b - b + a) - 4 a b + 2 b - a.

Grouping like terms, 3 a - 2 b - a b - (a b - b + a) - 4 a b + 2 b - a = -(a b - b + a) + (-a b - 4 a b) + (3 a - a) + (2 b - 2 b):

-(a b - b + a) + (-a b - 4 a b) + (3 a - a) + (2 b - 2 b)

Hint: | Combine like terms in -a b - 4 a b.

a b (-1) + a b (-4) = -5 a b:

-(a b - b + a) + -5 a b + (3 a - a) + (2 b - 2 b)

Hint: | Combine like terms in 3 a - a.

3 a - a = 2 a:

-(a b - b + a) - 5 a b + 2 a + (2 b - 2 b)

Hint: | Look for the difference of two identical terms.

2 b - 2 b = 0:

-(a b - b + a) - 5 a b + 2 a

Hint: | Distribute -1 over a b - b + a.

-(a b - b + a) = -a b + b - a:

-a b + b - a - 5 a b + 2 a

Hint: | Group like terms in -a b - 5 a b + b + 2 a - a.

Grouping like terms, -a b - 5 a b + b + 2 a - a = (-a b - 5 a b) + b + (-a + 2 a):

(-a b - 5 a b) + b + (-a + 2 a)

Hint: | Combine like terms in -a b - 5 a b.

a b (-1) + a b (-5) = -6 a b:

-6 a b + b + (2 a - a)

Hint: | Combine like terms in 2 a - a.

2 a - a = a:

Answer: -6 a b + b + a

8 0
3 years ago
Pls help I need explanation if u can
trapecia [35]

Answer:

15√15−15√5+15√3−15

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

Exact Form: 15√15−15√5+15√3−15

Decimal Form: 35.53449264…

4 0
3 years ago
Simplify (5x-5)-1(x+8
Nataliya [291]

simplified is

4x-13

4 0
3 years ago
a group of students attend a math club half the students are boys and 4/9 of the boys have brown eyes what fraction of the group
enyata [817]
From the whole group half the club are boys. 
fraction of boys from the whole class = 1/2
from this fraction, 4/9th of the boys have brown eyes
therefore fraction of boys who have brown eyes 
= 4/9 of 1/2
the 'of' function is used to multiply 
\frac{4}{9} *  \frac{1}{2}
when multiplying fractions numerators are multiplied by numerators and denominators multiplied by denominators
\frac{4*1}{9*2} =  \frac{4}{18}
4/18 can be simplified by dividing the whole number by a common number
4/18 divided by 2 = 2/9
the answer is 2/9
2/9 of the club are boys with brown eyes


3 0
3 years ago
Read 2 more answers
Robert bought 24 chicken wings for $57.60. How much would it cost for 22 wings?
horsena [70]
Roberta it would cost 52.80 for 22 wings
6 0
3 years ago
Read 2 more answers
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