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3 years ago

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Which of the following is the correct conversion rate to multiplied by an order to convert from miles per second to yards per se

cond
A:1760s/1yd
B:1760mi/1s
C:1760yd/1mi
D:1mi/1760yd

1 answer:

elixir [45]3 years ago

4 0

Answer:

i dont even know duh

Step-by-step explanation:

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Someone please helppp ! i’ll give brainliest to the right answer !

Nuetrik [128]

Answer:

The function is 2 I believe

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the composite function (please help)

anastassius [24]

Answer:

(f o h)(x) = -10x + 32

General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

<u>Algebra I</u>

Composite Functions

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 2x³ + 8

h(x) = ∛(12 - 5x)

(f o h)(x) is f(h(x))

<u>Step 2: Find Composite Function</u>

Substitute: (f o h)(x) = 2(∛(12 - 5x))³ + 8
Evaluate: (f o h)(x) = 2(12 - 5x) + 8
Distribute 2: (f o h)(x) = 24 - 10x + 8
Combine like terms: (f o h)(x) = -10x + 32

And we have our final answer!

8 0

2 years ago

Why is it sometimes easier to open an account with a bank rather than with a credit union?

Vlada [557]

It is probably easier to open an account with a bank rather than with a credit union because most credit unions require a kind of affiliation, but banks will let anyone with money to open an account. The correct option among all the options that are given in the question is the first option or option "a".

Hope this helps!

7 0

3 years ago

DiKsa [7]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to simplify:

$\displaystyle \frac{a+2}{a^2+a-2}+\frac{3}{a^2-1}$

First, let's factor the denominators of each term. For the second term, we can use the difference of two squares. Hence:

$\displaystyle =\frac{a+2}{(a+2)(a-1)}+\frac{3}{(a+1)(a-1)}$

Now, create a common denominator. To do this, we can multiply the first term by (<em>a</em> + 1) and the second term by (<em>a</em> + 2). Hence:

$\displaystyle =\frac{(a+2)(a+1)}{(a+2)(a-1)(a+1)}+\frac{3(a+2)}{(a+2)(a-1)(a+1)}$

Add the fractions:

$\displaystyle =\frac{(a+2)(a+1)+3(a+2)}{(a+2)(a-1)(a+1)}$

Factor:

$\displaystyle =\frac{(a+2)((a+1)+3)}{(a+2)(a-1)(a+1)}$

Simplify:

$\displaystyle =\frac{a+4}{(a-1)(a+1)}$

We can expand. Therefore:

$\displaystyle =\frac{a+4}{a^2-1}$

Problem 2)

We want to simplify:

$\displaystyle \frac{1}{(a-b)(b-c)}+\frac{1}{(c-b)(a-c)}$

Again, let's create a common denominator. First, let's factor out a negative from the second term:

$\displaystyle \begin{aligned} \displaystyle &= \frac{1}{(a-b)(b-c)}+\frac{1}{(-(b-c))(a-c)}\\\\&=\displaystyle \frac{1}{(a-b)(b-c)}-\frac{1}{(b-c)(a-c)}\\\end{aligned}$

Now to create a common denominator, we can multiply the first term by (<em>a</em> - <em>c</em>) and the second term by (<em>a</em> - <em>b</em>). Hence:

$\displaystyle =\frac{(a-c)}{(a-b)(b-c)(a-c)}-\frac{(a-b)}{(a-b)(b-c)(a-c)}$

Subtract the fractions:

$\displaystyle =\frac{(a-c)-(a-b)}{(a-b)(b-c)(a-c)}$

Distribute and simplify:

$\displaystyle =\frac{a-c-a+b}{(a-b)(b-c)(a-c)}=\frac{b-c}{(a-b)(b-c)(a-c)}$

Cancel. Hence:

$\displaystyle =\frac{1}{(a-b)(a-c)}$

4 0

3 years ago

PLEASE HELP!!!!!!!!!

kolezko [41]

Let $x_1 , x_2$ be the roots of the equation $3x^2-5x-7$ . By the Viet theorem you have that $\left \{ {{x_1+x_2=- \frac{5}{3} } \atop {x_1x_2= \frac{-7}{3} }} \right.$ .

For the equation $x^2+bx+c = 0$ you'll have that $c=(x_1+2)(x_2+2)=x_1x_2+2(x_1+x_2)+4=\frac{-7}{3}+2\cdot(- \frac{5}{3} )+4$
That is $\frac{-7}{3}- \frac{10}{3} +4=- \frac{5}{3}$ .

Answer: $- \frac{5}{3}$

4 0

3 years ago