Answer:
y + 30 = 4/5(x - 10)
Step-by-step explanation:
Given the slope, 4/5, and point (10, -30):
We can plug these values into the point-slope form:
y - y1 = m(x - x1)
Let (x1, y1) = (10, -30)
and m = 4/5
y - (-30) = 4/5(x - 10)
y + 30 = 4/5(x - 10)
Therefore, the point-slope form is y + 30 = 4/5(x - 10)
The answer is x=-2
As you could see, this is a factored function.
The un-factored version is x^2+4x-12
-b/2a=x
-4/2=-2= x of vertex
Answer:
make a table of values
Step-by-step explanation:
then plot using those values
Answer:
1) The terminal side lies in quadrant 2
2) cosФ = -15/17
3) tanФ = -8/15
Step-by-step explanation:
1) First, we should realize that since sinФ = 8/17, it is positive. Thus, Ф must be in quadrants 1 or 2. And since cosФ is negative, Ф must be in quadrant 2 because cos, sin, and tan are all positive in quadrant 1
2) Next, we must realize that the sides given are a 8-15-17 right triangle. And in this case, since sinФ = 8/17, cosФ should be 15/17. But since cosФ is negative, cosФ = -15/17
3) Lastly, tanФ is opposite/adjacent. Since opposite of Ф is 8 and adjacent of Ф is 15, then tanФ should be 8/15, but since Ф is in quadrant 2, then tanФ is -8/15
Answer:
Step-by-step explanation:
