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Pavel [41]
3 years ago
13

Help please i give brainliast)

Mathematics
2 answers:
masha68 [24]3 years ago
7 0

x|y............................

5|10

6|20

6|23

7|35

siniylev [52]3 years ago
5 0

on the chart you just write the coordinates it gives above

and graph it

the other part write like this

5  -----> 10

6------->20 &30

7--------> 35

You might be interested in
-2(x-5)=6(2- 1/2x)<br><br> Please show your work. Distributive property, remove variable
schepotkina [342]

The solution of given equation is x=2

Further explanation:

In order to solve the given equation we have to isolate the variable x on one side of the equation. The process will involve distributive property and simplification.

Given:

-2(x-5)=6(2-\frac{1}{2}x)\\Apply\ distributive\ property\\-2x-2(-5)=(6)(2)-(6)(\frac{1}{2}x)\\-2x+10=12-\frac{6}{2}x\\-2x+10=12-3x\\-2x+3x=12-10\\x=2

The solution of given equation is x=2

Keywords: Linear Equation, Distributive property

Learn more about linear equations at:

  • brainly.com/question/10169676
  • brainly.com/question/10208427

#LearnwithBrainly

6 0
4 years ago
5/6+5/6 show your work
Umnica [9.8K]
10/6 = 1 2/3 This is because 5 + 5 =10/6 Divide 19 by six. This gives you 1 2/3
6 0
3 years ago
What makes a constant term different from a term with a variable?
Sunny_sXe [5.5K]
A constant is any number, anywhere on the number line.
A variable is an unknown, x y z n etc
8 0
3 years ago
Read 2 more answers
A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate
neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:  

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate  munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

C-2=\frac{1}{11}*(C+D-2)...(1)

We are also told if he instead added 4  glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

C=\frac{1}{7}*(C+D+4)...(2)

Upon substituting C's value from equation (2) in equation (1) we will get,

\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)

Let us have a common denominator on right side of equation.

\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)

\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)

Multiplying both sides of our equation by 7, we will get,

7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)

C+D-10=\frac{7}{11}*(C+D-2)  

Multiplying both sides of our equation by 11, we will get,

11*(C+D-10)=11*\frac{7}{11}*(C+D-2)  

11*(C+D-10)=7*(C+D-2)

11C+11D-110=7C+7D-14

11C-7C+11D-7D=-14+110  

4C+4D=96

4(C+D)=96  

(C+D)=\frac{96}{4}

(C+D)=24

Therefore, the total number of Munchkins in original box is 24.

3 0
3 years ago
|x+1|&lt;4 please and thank youuuu
user100 [1]

Answer:

-5,3

Step-by-step explanation:

4 0
3 years ago
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