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tamaranim1 [39]
3 years ago
6

Write in point-slope form an equation of the line that passes through the point (6,−1) with slope −1/3.

Mathematics
2 answers:
lesya [120]3 years ago
7 0

Answer:

y=-\frac{1}{3} x-3

Step-by-step explanation:

If you graph the equation, you'll see that the y-intercept is -3 and the slope is \frac{1}{3}

SSSSS [86.1K]3 years ago
6 0

Answer:

y-1=-\frac{1}{3}\left(x-0\right)

Step-by-step explanation:

I graphed the equation on the graph below. I used the slope and the point given to create the equation of the line.

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Solve this A tourist starts off from town A and travels for 50km on a bearing of N80°W to town B.At town B ,he continues for ano
VLD [36.1K]

Answer:

The point C is 12.68 km away from the point A on a bearing of S23.23°W.

Step-by-step explanation:

Given that AB is 50 km and BC is 40 km as shown in the figure.

From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|

=|50 sin 80° - 40 cos 20°|=11.65 km

The length of y-component of AC = |AB cos 80° - BC sin 20°|

=|50 cos 80° - 40 sin 20°|= 5 km

tan\theta= 5/11.65

\theta=23.23°

AC= \sqrt{5^2+11.65^2}=12.68 km

Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.

8 0
2 years ago
In a triangle the first angle is greater than the second angle by 18 degree and less than the third angle by 10 grade. Express a
serg [7]

Answer:

The 3 angles are 62 2/3, 44 2/.3 and 72 2/3 degrees.

Step-by-step explanation:

let x be the first angle then the  the second angle is  x - 18 and the third angle = x + 10

The 3 angles add up to 180 so:

x + x - 18 + x + 10 = 180

3x = 180 + 18 - 10 = 188

x = 188/3 = 62 2/3 degrees.

x - 18 = 44 2/3

x + 10 = 72 2/3.

8 0
2 years ago
The following question has two parts. First, answer part A. Then, answer part B.
Pie

Answer:

When you're talking factors, you're talking about some sort of integer; that's because “factors” depends on the concept of divisibility, which are virtually exclusive to integers. When you're talking “greater than”, you're excluding complex numbers (where the concept of ordering doesn't exist) and you're probably assuming positive integers. If you are, then no; no positive integer has factors that are larger than it.

If you go beyond positive numbers, that changes. 0 is an integer, and has every integer, except itself, as factors; since its positive factors are greater than zero, there are factors of zero that are greater than zero. If you extend to include negative numbers, you always have both positive and negative factors; and since all positive integers are greater than all negative integers, all negative integers have factors that are greater than them.

Beyond zero, though, no integer has factors whose magnitudes are greater than its own. And that's a principle that can be extended even to the complex integers

Step-by-step explanation:

8 0
2 years ago
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