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lbvjy [14]
3 years ago
10

What are the domain and range of the function? f(x) = ^3 square x - 3

Mathematics
1 answer:
DerKrebs [107]3 years ago
4 0

Step-by-step explanation:

f(x) = \sqrt[3]{x - 3}

The domain of a function are the values of x that you can plug into the function f(x).

Values inside of a root must be non-negative, which means that x - 3 must be greater than or equal to zero. We can set up an equation to find the domain:

x - 3 \geq 0

x \geq 3

With this, we know the domain of the function is [3, \inf).

The range of a function are the values that f(x) can have. Since the equation is a cube root, the value will always be non-negative, meaning the range of the function is [0, \inf).

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HELP ASAP!
enot [183]

Answer:

I believe the answer is (-1,5)

Step-by-step explanation: because when you draw it out on a coordinate plain (-1,5) lies right in the middle of these two points.

4 0
3 years ago
Please tell me? thx for ur help <3
motikmotik

Answer:

x = 63, y = 27

Step-by-step explanation:

x and 117 are adjacent angles and sum to 180°

x + 117 = 180 ( subtract 117 from 180 )

x = 63

x and y sum to 90°

x + y = 90

63 + y = 90 ( subtract 63 from both sides )

y = 27

4 0
3 years ago
Read 2 more answers
5.607 is what percent of 89 step by step
MrMuchimi

Answer:

6.3%

Step-by-step explanation:

so 5.607 = x% * 89

to find the percent u need to divide : 5.607/89 which is : 0.063

to convert 0.063 to a percent multiply 0.063 by 100 = 6.3%

check :

6.3% *89 = 5.607

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3 years ago
Which expression is equivalent to (x^4/3 x^2/3)^1/3?
Georgia [21]
The answer is B, x^2/3
7 0
3 years ago
Read 2 more answers
For which operations is the set {0, 1} closed?
velikii [3]
0 × <span>0 = 0
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1 </span>× <span>1 = 1

Which means multiplication is closed under {0, 1}

</span><span>1 </span>÷ <span>1 = 1
0 </span>÷ <span>1 = 0
</span>
Division is not closed under {0, 1}

1 + 1 = 2

Addition is not closed under {0, 1}

0 - 1 = -1

Subtraction is not closed under {0, 1} either



So it's only A. Multiplication which is closed under {0, 1}
5 0
3 years ago
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