Question

What are the solutions to the equation 3x^2 + 15x = 18. Show your work.

Answer 1

Answer: x1=1

x2=-6

Step-by-step explanation:

3x^2+15x-18=0

D^2=225-4*3*(-18)/6=411

D=21

x1=(-15+21)/6=1

x2=(-15-21)/6=-6

Answer 2

Assignment: $\bold{Solve \ Equation: \ 3x^2+15x=18}$

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Answer: $\boxed{\bold{x=1,\:x=-6}}$

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Explanation: $\downarrow\downarrow\downarrow$

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[ Step One ] Subtract 18 From Both Sides

$\bold{3x^2+15x-18=18-18}$

[ Step Two ] Simplify

$\bold{3x^2+15x-18=0}$

[ Step Three ] Solve With Quadratic Formula

Note: $\bold{For\:a\:quadratic\:equation\:of\:the\:form\: ax^2+bx+c=0}$

$\bold{the \ solutions \ are \ x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}}$

$\bold{a=3,\:b=15,\:c=-18:\quad x_{1,\:2}=\frac{-15\pm \sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}}$

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$\bold{\frac{-15+\sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}: \ 1}$

$\bold{\frac{-15-\sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}: \ -6}$

[ Step Four ] Combine Solutions

$\bold{x=1,\:x=-6}$

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$\bold{\rightarrow Mordancy \leftarrow}$