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Oksanka [162]
3 years ago
5

Question is provided in the image attached. 25 points!

Mathematics
1 answer:
earnstyle [38]3 years ago
7 0

Hey!

-------------------------------

Find the zero term:

Plug in 0 for n.

a = 8 + 3(0 - 1)

a = 8 + 3(-1)

a = 8 + (-3)

a = 5

Answer: 5

-------------------------------

Find the first term:

Plug in 1 for n.

a = 8 + 3(1 - 1)

a = 8 + 3(0)

a = 8 + 0

a = 8

Answer: 8

-------------------------------

Find the 40th term:

Plug in 40 for n.

a = 8 + 3(40 - 1)

a = 8 + 3(39)

a = 8 + 117

a = 125

Answer: 125

-------------------------------

Hope This Helped! Good Luck!

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Read 2 more answers
Example 2
PIT_PIT [208]

Answer: (a) 314.2cm², (b) 157.1cm², (c) 78.55cm² (e) 6.77

Step-by-step explanation: (a)  Area of the circle with radius of 10 cm = πr²

                                                                          = 3.142 × 10 × 10

                                                                          = 3.142 × 100

                                                                          = 314.2cm²

The formula                                                       = πr²

(b)  Area of the half of a circle known as semicircle

                                                                         = πr²/2

                                                                         = 3.142 ×10 × 10/2

                                                                         = 3.142 × 50

                                                                         = 157.1cm²

The formula                                                      = πr²/2

(c)  A quarter of a circle is called quadrant

                                                            = πr²/4

                                                            = 3.142 × 10 × 10/4

                                                            = 314.2/4

                                                            = 78.55cm²

The formula is written thus = πr²/4, which implies that the circle is divided into 4 unit

(d) The conjecture about how to determine the area of the sector is

Formula of a sector = ∅/360(πr²)

<u>Information</u>

The arc  cant be 60°, therefore information incomplete.

(e) Area of the sector with the angle AOB of 60° = 24.

To find the radius of the angle, make v the subject of the formula from the formula.

Sector area = πr²∅/360°

equate formula to 24.

Therefore πr²∅/360° = 24

Multiply through by360° to make it a linear expression

It now becomes πr²∅ =24× 360°

                                                     r² = 24  x 360/π × ∅°

                                                     r² = 24 × 360° /3.142 × 60°

                                                     r² = 3,640/188.52

                                                     r² = 45.8

To find r , we take the square root of both side by applying laws of indicies

                                    Therefore r = √45 .8

                                                      r = 6.77

(f)   General formula = ∅°/360° × (πr²)

angle substended at centre by the arc = x°

assuming the radius of the circle = ycm, Therefore,  area of the sector = { ∅°/360° × πy² }

                                                     

                                                   

8 0
3 years ago
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