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3 years ago

Which graph represents the sequence: 1, 2.5, 4, 5.5, 7, ...? Draw a graph representing the sequence.

Mathematics

2 answers:

mariarad [96]3 years ago

8 0

So base on your question where there is a set of line graph in the choices and what could be the perfect graph that could have or be fit with this sequences 1, 2.5, 4, 5.5, 7. So base on your data i conclude that the slope of the graph is 1.5 and you just need to graph it and its a slanting line that has a slope of 1.5

Sunny_sXe [5.5K]3 years ago

7 0

Answer:

Attachment

Step-by-step explanation:

Given: Sequence of number:- 1, 2.5, 4, 5.5, 7, ....

First we find the formula of the sequence

First term, a₁=1

Second term, a₂=2.5

Common difference, d = a₂ - a₁

d = 2.5 - 1 = 1.5

Formula:

$a_n=a+(n-1)d$

$a_n=1 + (n-1)1.5$

$a_n=1+1.5n-1.5$

$a_n=1.5n-0.5$

So, function of the sequence will be

$f(n)=1.5n-0.5$

This is equation of straight line. Now, we draw the graph of function.

Make table of n and f(n)

n : 1 2 3 4 5

f(n): 1 2.5 4 5.5 7

Plot the points on graph. Please see attachment for graph.

Domain of function: n≥1

Because sequence is start from 1.

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Read 2 more answers

Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure

Marina CMI [18]

Answer:

a) $P(0.11$

And we can find this probability with this difference and with the normal standard table or excel:

$P(-1.11$

b) $P(0.11 < \bar X < 0.13)$

And we can use the z score defined by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using the limits we got:

$z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22$

$z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22$

And we want to find this probability:

$P(-2.22< Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

$X \sim N(0.12,0.009)$

Where $\mu=0.12$ and $\sigma=0.009$

We are interested on this probability

$P(0.11$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(0.11$

And we can find this probability with this difference and with the normal standard table or excel:

$P(-1.11$

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by: