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Mashutka [201]
2 years ago
12

Defective components: A lot of 9 components contains 4 that are defective. Two components are drawn at random and tested. Let A

be the event that the
first component drawn is defective, and let B be the event that the second component drawn is defective. Write your answer as a fraction or a decimal, rounded
to four decimal places.
(a) Find P(A).
(b) Find P(BLA).
(c) Find P4 and B).
(d) Are A and B independent? Explain.
Mathematics
1 answer:
dusya [7]2 years ago
8 0
Umm I have no Idea sorry
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12+98=<br> really confused on this one
kipiarov [429]

Answer:

12+98=110

Step-by-step explanation:

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Robin surveyed 5 students from the choirs of 4 different schools. He asked them how many hours they practice singing each day. S
Fittoniya [83]

Answer:

The highest would be the letter B and the lowest would be letter C if the pat is what you need to know.

Hope it helps :)

3 0
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Helppp! idk why its needs to be 20 charactes so i wrote this
marin [14]
This should be 1.35, sorry if it’s wrong
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According to a Washington Post-ABC News poll, 331 of 502 randomly selected U.S. adults interviewed said they would not be bother
k0ka [10]

Answer:

z=\frac{0.659 -0.5}{\sqrt{\frac{0.5(1-0.5)}{502}}}=7.124  

p_v =P(z>7.124)=5.24x10^{-13}  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is significantly higher than 0.5.  

Step-by-step explanation:

Data given and notation

n=502 represent the random sample taken

X=331 represent the adults that said they would not be bothered if the NAtional security agency

\hat p=\frac{331}{502}=0.659 estimated proportion of people who would not be bothered if the NAtional security agency

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than the majority of 0.5:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.659 -0.5}{\sqrt{\frac{0.5(1-0.5)}{502}}}=7.124  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>7.124)=5.24x10^{-13}  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is significantly higher than 0.5.  

4 0
3 years ago
Please someone help me I'm stuck on my homework for at least a hour
miss Akunina [59]

Pi is 3.14

1st # is 3.13

2nd # is 3.15

These numbers are irrational because pi=infinity

( I am not exactly sure if this is right so don't blame me if you get this wrong, I just tried to help.....) :T

6 0
3 years ago
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