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Mashutka [201]
2 years ago
12

Defective components: A lot of 9 components contains 4 that are defective. Two components are drawn at random and tested. Let A

be the event that the
first component drawn is defective, and let B be the event that the second component drawn is defective. Write your answer as a fraction or a decimal, rounded
to four decimal places.
(a) Find P(A).
(b) Find P(BLA).
(c) Find P4 and B).
(d) Are A and B independent? Explain.
Mathematics
1 answer:
dusya [7]2 years ago
8 0
Umm I have no Idea sorry
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Graph the linear equation by plotting the x and y intercepts <br> x +4y -16 =0
ira [324]

Answer:

x intercept = 16

y intercept = 4

Step-by-step explanation:

For the x intercept...y = 0...where the equation would be...x + 4(0) = 16..hence giving us the x intercept as... x = 16

For the y intercept...x = 0...where if we substitute x = 0 into our equation...the equation would be....0 + 4y = 16..hence giving us..., 4y = 16...divide both sides by 4...y = 4

5 0
3 years ago
The sum of (2a + ab + 2b) + (4a2 - 3ab + 9)
Sati [7]
You can only add/subtract like terms so:

2a+ab+2b+4a^2-3ab+9

2a-2ab+2b+4a^2+9  (the only like terms were ab and -3ab)
4 0
3 years ago
Simplify ( √ 5)(^3 √ 5) the answer will be a wholenumber and a fraction
arlik [135]

Answer:

\sqrt{5}\cdot\sqrt[3]{5} =\sqrt[6]{5^3} \cdot\sqrt[6]{5^2} =\sqrt[6]{5^5} =5^{(5/6)}

Step-by-step explanation:

The rules of exponents apply, even when they are fractional exponents:

a^b\cdot a^c=a^{b+c}\\\\\sqrt[b]{x^a}=x^{(a/b)}

6 0
3 years ago
Please help i will give you brainliest and every yhing
Lina20 [59]

first subtract the last equation from the first. this gives:-

-x + y = -8 .....................(1)

Then multiply the first equation by 2 and add it to the 2nd equations This gives

9x = 18  

so x = 2

and from equation  (1)  y = -8 + 2 = -6

Substituting for x and y in the second equation

z =  (24 -5(2) -12) / 2 =   1


Answer is choice b.

7 0
2 years ago
A plumber charges a base fee of $55 for service call plus &amp;35 per hour for each hour worked during the service call. Write a
Tasya [4]

Answer:

  p = 55 + 35h

Step-by-step explanation:

Let p and h represent the price of the service call and the hours worked, respectively. The price charged is 35 dollars for each hour, so the time-based part of the price is 35h. The base fee of 55 dollars is added to that for a total price of ...

  p = 55 + 35h

5 0
3 years ago
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