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katrin2010 [14]
4 years ago
7

Question 1 :George, a user, is having trouble connecting to network resources, including shared folders on the local network and

Internet resources. Yesterday, he was able to connect with no problems. You need to ensure that he can connect to these resources. Which tool should you use FIRST?
Computers and Technology
1 answer:
vazorg [7]4 years ago
4 0

Complete Question:

George, a user, is having trouble connecting to network resources, including shared folders on the local network and Internet resources. Yesterday he was able to connect with no problems. You need to ensure that he can connect to these resources. Which tool should you use FIRST?

Group of answer choices

A. ipconfig

B. Device Manager

C. My Network Places

D. Control Panel

Answer:

A. ipconfig

Explanation:

As a network administrator, to ensure that George can connect to the network resources, shared folders, and internet resources, the tool you should use first is the "ipconfig" in the command line. This is a troubleshooting process that would help to identify the problem and to establish a theory of probable cause.

<em>Since George could connect the previous day without any problem, it is most likely that the TCP/IP settings has been altered. Therefore, to view this settings you'll have to use an ipconfig command. </em>

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In class, we discussed static local variables in C. Answereach question below; if necessary, find and consult a reference on the
alexira [117]

Answer:

(a) scope: function, lifetime: duration of the function

(b) scope: function, lifetime: duration of the program

(c) scope: global (all modules),  lifetime: duration of the program

(d) scope: module (file), lifetime: duration of the program

6 0
3 years ago
A rang check that could be use to validate... Date and time
lisov135 [29]

A range check is often used when a person works with data consisting of numbers, dates and times, or currency, ensuring that a number is within a specific range.

Explanation:

  • Range checks allow a person to set suitable boundaries.
  • An example of a range check is checking to see if the value of a 16-bit integer is within the capacity of a 16-bit integer. When a range check is performed, upper and lower boundaries are specified.
  • Range check is a validation check which can be applied to numeric fields. This is done to ensure that only numbers within a certain domain can be entered into a field. Remember that this does not necessarily mean that the data entered will be correct. But it will certainly lie within reasonable limits.
  • A method of validation which checks that data falls between an upper and lower acceptable value.
  • This validation check which can be applied to numeric fields. This is done to ensure that only numbers within a certain domain can be entered into a field. Remember that this does not necessarily mean that the data entered will be correct. But it will certainly lie within reasonable limits.
5 0
3 years ago
Using Sequential Search on an array of size n, the search key is definitely present in the array. The probability of matching th
MissTica

Answer:

(11n-5) / 12 is correct answer.

Explanation:

The Probability that key will match to nth term = 1/2

The Probability that key will match to n-1th term = 1/3

As all other probabilities are equal

The Total Probability that key matches to any of 1 to n-2 index = 1 - 1/2 - 1/3 = 1/6

The Probability that key matches to any of 1 to n-2 index = (1/6) / n-2 = (1/6)* (n-2))

Let P(i) = Probability that key matches to ith index.

The Average time complexity = 22 i=1 P(i) * i

The Average time complexity = 1/(6(n-2) * ( sum of 1 to n-2 ) + (n-1) / 3 + n/2

The Average time complexity = 1/(6(n-2) * ( n-2)*(n-1) / 2 + ( n-1) / 3 + n/2

The Average time complexity = 1/6 * (n-1)/2 + (n-1)/3 + n/2

The Average time complexity = (n-1)/12 + (n-1)/3 + n/2

The Average time complexity = (n-1 + 4 * n - 4 * 1 +6 * n)/12

The Average time complexity = 11n-5 / 12

so (11n-5) / 12 is correct answer.

7 0
3 years ago
(a) Store last 7 digits of your student ID in a vector (7 element row or column vector). Write a MATLAB code which creates a 7x7
astra-53 [7]

Answer:

MATLAB code explained below with appropriate comments for better understanding

Explanation:

clc

clear all

ID = [1 2 3 4 5 6 7]; % Replace this with your student ID

%(a)

A = zeros(7);

for i=1:7

 

A(i,i)= ID(i);

 

end

fprintf('A =\n');

disp(A);

B = diag(ID);

fprintf('B =\n');

disp(B);

fprintf('Both A and B are same\n');

%(b)

if(mod(A(6,6),2)==0)

fprintf('A(6,6) is even\n');

else

fprintf('A(6,6) is odd\n');

end

%(c)

if(A(3,3)>0)

fprintf('A(3,3) is positive\n');

else if(A(3,3)<0)

fprintf('A(3,3) is negative\n');

else

fprintf('A(3,3)=0\n');

end

end

%(d)

fprintf('\nRequired series : ');

n = 35;

while n>=0

fprintf('%i',n);

if(n>0)

fprintf(', ');

end

n = n - 5;

end

fprintf('\n');

%(e)

n = input('\nInput an integer : ');

fprintf('%i! = ',n);

F = 1;

while n>1

F = F * n;

n = n - 1;

end

fprintf('%i\n',F);

%(f)

clear all

x = [3 7 2 1];

y = [4 3 9 1];

A = 0;

C = x(1);

for i=1:length(x)

A = A + x(i)*y(i);

B(i) = x(i)/y(i);

if(min(x(i),y(i))<C)

C = min(x(i),y(i));

end

end

C = 1/C;

fprintf('\nA = %i\n',A);

fprintf('B = ');

disp(B)

fprintf('C = %0.5g\n',C);

%(g)

clear all

A = randi([5 25],[1,10]);

maxA = A(1);

for i = 2:10

if(maxA<A(i))

maxA = A(i);

end

end

minA = A(1);

i = 2;

while i<11

if(minA>A(i))

minA = A(i);

end

i = i+1;

end

fprintf('\nA = ');

disp(A);

fprintf('maxA = %i\n',maxA);

fprintf('minA = %i\n',minA);

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%output

A =

1 0 0 0 0 0 0

0 2 0 0 0 0 0

0 0 3 0 0 0 0

0 0 0 4 0 0 0

0 0 0 0 5 0 0

0 0 0 0 0 6 0

0 0 0 0 0 0 7

B =

1 0 0 0 0 0 0

0 2 0 0 0 0 0

0 0 3 0 0 0 0

0 0 0 4 0 0 0

0 0 0 0 5 0 0

0 0 0 0 0 6 0

0 0 0 0 0 0 7

Both A and B are same

A(6,6) is even

A(3,3) is positive

Required series : 35, 30, 25, 20, 15, 10, 5, 0

Input an integer : 6

6! = 720

A = 52

B = 0.7500 2.3333 0.2222 1.0000

C = 1

A = 25 14 7 10 13 17 10 17 19 9

maxA = 25

minA = 7

>>

5 0
3 years ago
Write a procedural programming loop.. Your loop should start variable n with a value of 10 and count down to zero. The loop shou
anastassius [24]

Answer:

//Here is the for loop in C.

for(n=10;n>0;n--)

{

   printf("count =%d \n",n);

}

Explanation:

Since C is a procedural programming language.Here if a loop that starts with n=10; It will run till n becomes 0. When n reaches to 0 then loop terminates otherwise it  print the count of n.

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{  // variables

int n;

// for loop that runs 10 times

// when n==0 then loop terminates

for(n=10;n>0;n--)

{

   cout<<"count ="<<n<<endl;

}

return 0;

}

Output:

count =10

count =9

count =8

count =7

count =6

count =5

count =4

count =3

count =2

count =1

3 0
4 years ago
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