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mixas84 [53]
3 years ago
10

B(x)=|x+4| what is b(-20)​

Mathematics
1 answer:
sattari [20]3 years ago
4 0

Answer:

16

Step-by-step explanation:

plug in -20 for x to get |-20+4|

that is |-16| but the absolute value of it is 16

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Can someone please help me on this asap?? Im begging ill give more points and brainliest etc just please please help.
navik [9.2K]

Answer:

which one and I will help

8 0
2 years ago
Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe
nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let D^c be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that  one person in 10,000 people has a rare genetic disease.

So,P(D)=\frac{1}{10000}

Only 0.4% of the people who don't have it test positive.

P(A|D^c) = probability that a person is tested positive given he don't have a disease = 0.004

P(D^c)=1-\frac{1}{10000}

Formula:P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}

P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}

P(D|A)=\frac{2470}{2471}=0.9995

P(D|A)=0.9995

A)The probability that someone who tests positive has the disease is 0.9995

(B)

P(D^c|A^c)=probability that someone does not have disease given that he tests negative

P(A^c|D^c)=probability that a person tests negative given that he does not have disease =1-0.004

=0.996

P(A^c|D)=probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}

P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}

P(D^c|A^c)=0.99999

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0
4 years ago
TJ invested $4000 in a bond at a yearly rate of 2%. He earned $200 in interest. How long was the money invested
kow [346]

4000.00 x 2.0 = $80.00 per year x 2 years = $160.00 so 6 months would earn $40.00 taking it to the $200, so 2 yrs 6 mos.



3 0
3 years ago
Divide.<br>(2x²+17x+28)÷(x+6)<br>​
oksian1 [2.3K]

Answer:

2x2+17x+28/x+6

Step-by-step explanation:

6 0
3 years ago
Please help!! | show work and do not guess. :)
Olegator [25]
The answer would be b A≈1636.8
8 0
3 years ago
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