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Genrish500 [490]
3 years ago
5

Write the equation of a line that is perpendicular to y=-4/3x+9 and goes through (8,-5). Do not use spaces in your answer. Enter

fractions as a/b as seen in the given equation. PLEASE HELP ME PLEAEEEEEE

Mathematics
1 answer:
liq [111]3 years ago
8 0

Answer:

y=3/4x-11

Step-by-step explanation:

When a line is perpendicular to another line, their slope is the opposite reciprocal of that. So in this case, the slope of the perpendicular line would be positive 3/4. Next, plug in the points (8,-5) in the y=mx+b formula along with the new slope. In conclusion, the new point slope formula is y=3/4x-11.

Hope this helps! :)

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6 points and brainliest answer No.1
gizmo_the_mogwai [7]
The answer is B.) 14 :):):):)
3 0
3 years ago
The equation p(t) = 1.e represents a
zvonat [6]

Answer:

(b), (d) and (e)

Step-by-step explanation:

Given

p(t) = 1 * e^t

See attachment for y = p(t)

Required

Select true statements from the given options

(a) \ln(30) = days the bacteria reaches 30000

We have:

p(t) = 1 * e^t

In this case:

t = \ln(30) and p(t) = 30000

So, we have:

30000 = 1 * e^{\ln(30)}

30000 = e^{\ln(30)}

Using a calculator, we have:

e^{\ln(30)} = 30

So:

30000 = 30

The above equation is false.

(a) is not true

(b) The graph shows that \ln(20) \approx 3

We have:

p(t) = 1 * e^t

Let t = 3

So;

p(3) = 1 * e^3

From the graph, p(3) = 20

So:

20 = 1 * e^3

20 = e^3

Take natural logarithm of both sides

\ln(20) = \ln(e^3)

This gives:

\ln(20) = 3

(b) is true

(c) \ln(t) = y is the logarithm form of y = e^t

We have:

y = e^t

Take natural logarithm of both sides

\ln(y) = \ln(e^t)

This gives:

\ln(y) = t

\ln(y) = t  \ne \ln(t) = y

(c) is false

(d) e^4 > 50 and  \ln(50) < 4

From the graph, we have:

e^4 = 54 --- rough readings

This implies that:

e^4 > 50 is true

Because 54 > 50

Take natural logarithm of both sides

\ln(54) > \ln(50)

Rewrite as:

\ln(50) < \ln(54)

We have:

e^4 = 54

Take natural logarithm of both sides

\ln(e^4) = \ln(54)

4 = \ln(54)

\ln(54) = 4

Substitute \ln(54) = 4 in \ln(50) < \ln(54)

\ln(50) < 4

(d) is true

(e) The graph shows that 10 \approx \ln(2.3)

We have:

p(t) = 1 * e^t

Let t = 2.3

So;

p(2.3) = 1 * e^{2.3}

From the graph,

p(2.3) = 10 ---- rough readings

So:

10 = 1 * e^{2.3}

10 = e^{2.3}

Take natural logarithm of both sides

\ln(10) = \ln(e^{2.3})

This gives:

\ln(10) = 2.3

(e) is true

4 0
3 years ago
which equation represents a line that is parallel to the line whose equation is 3x-2y=7; which equation represents a line parall
aleksley [76]

The equation of the line that is parallel to the line whose equation is 3x-2y=7 would be y = 3/2x + b, in which b can be any real number.

How are parallel straight lines related?

Parallel lines have the same slope since the slope is like a measure of steepness and since parallel lines are of the same steepness, thus, are of the same slope.

We have been given a parallel line with has equation

3x-2y=7

In order to solve this, the slope of the original line.

3x - 2y = 7

-2y = -3x + 7

y = 3/2x - 7/2

thus its slope is 3/2.

thus, the slope of the needed line is 3/2 too.

we know that any line that is parallel to that would have this slope.

So anything is written in the form:

y = 3/2x + b

The equation of the line that is parallel to the line whose equation is 3x-2y=7 would be y = 3/2x + b, in which b can be any real number.

Learn more about parallel lines here:

brainly.com/question/13857011

#SPJ4

3 0
1 year ago
The distance between Capeton and Jonesville is 80 miles. The scale on the map is 0.75 in. : 10 miles. How far apart are the citi
Mnenie [13.5K]
The answer to this question is 6 in. Hope this helps.
7 0
4 years ago
A tree 7 ft tall grows an average of 6 in. each year. Which equation models the tree’s height h after x years?
Vesna [10]
The initial height of the tree = 7 ft

Each year the tree grows 6 in.   6 in = 6 / 12 = 0.5 ft

So the tree grows 0.5 ft every year.

After x years, the tree would have grown extra = 0.5*x =0.5x

So the height of the tree would be = Initial height + extra height grown

= 7 + 0.5x

h = 7 + 0.5x

Model is    h = 7 + 0.5x, 

where h = height of the tree in feet after x years. 

Hope this explains it.
6 0
3 years ago
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