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lesya [120]
3 years ago
11

Two sides of a triangle have the same length. The third side measures 3 m less than twice the common length. The perimeter of th

e triangle is 13 m. What are the lengths of the three​ sides?
Mathematics
1 answer:
Ksivusya [100]3 years ago
3 0

Answer:

4m, 4m, and 5 m

Step-by-step explanation:

From the information give;

  • Two sides of a triangle are equal in length
  • The third side is 3 m less than the common length
  • Perimeter of the rectangle is 13 m

We are required to determine the dimensions of the triangle;

  • Assuming the common sides are x m each
  • Then, the third side will be (2x-3) m
  • Perimeter of a triangle is equal to the sum of the lengths of the three sides

Therefore;

(2x-3) + x + x = 13 m

4x - 3 = 13m

4x = 16 m

x = 4 m

and, 2x-3 = 5 m

Therefore, the lengths of the three sides of the triangle are 4m, 4m, and 5 m

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Answer:

You have 15 dimes. You have 9 quarters. You have 12 nickels

Step-by-step explanation:

lets set some variables:

let "n" = the number of nickels

let "d" = the number of dimes

let "q" = the number of quarters

So, the total amount of money you have should be: $4.35 = 0.25q + 0.10d + 0.05n

Now let's look at the relationships between the coins:

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\left \{ {{4.35 = 0.25q + 0.10d + 0.05n} \atop {n - 3 = q}} \atop {q + 6 = d}}\right.

first, you can substitute "n-3" for "q" (according to the 2nd equation) in the 1st and 3rd equation, you get:

\left \{ {{4.35=0.25(n-3)+0.10d+0.05n} \atop {(n-3)+6=d}} \right.

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Simplify:

\left \{ {{4.35=0.25n-0.75+0.10d+0.05n} \atop {n+3=d}} \right.

\left \{ {{4.35=0.30n-0.75+0.10d} \atop {n+3=d}} \right.

Now substitute "n+3" for "d" (according to the 2nd equation) in the 1st equation:

4.35=0.30n-0.75+0.10(n+3)

simplify:

4.35=0.30n-0.75+0.10n+0.30

4.35=0.40n-0.45

4.35+0.45=0.40n

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