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2 years ago

GIVING BRAINLIEST!!! What’s 2 x2

Mathematics

2 answers:

Papessa [141]2 years ago

6 0

Answer:

Step-by-step explanation:

lutik1710 [3]2 years ago

3 0

Answer:

Step-by-step explanation:

2x2 is just 4 lol. I hope this helps lol

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Simplify the expressions

4vir4ik [10]

Answer:

1) 2(2x+3)

2) 2x+4

3) - X + 4

4) 9x - 2

5) 5x−2

6) - 12x - 17

7) - 15x + 11

8) 3x/4

9) - 4x + 7

10) 4x-26/2

11) - 8x + 20.8

12) x - 6

8 0

2 years ago

How do you write 2/11 as a decimal using long division

LuckyWell [14K]

Answer:

0.18

Step-by-step explanation: Converting the fraction 2/11 into a decimal is very easy. To get 2/11 converted to decimal, you simply divide 2 by 11.

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2 years ago

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Find the area of the figure. Assume all figures are made up of parallelograms and triangles.

rewona [7]

b. 60 m2

Find the area of the figure. Assume all figures are made up of parallelograms and triangles.

NOT:
b. 60 m2
c. 108 m2
d. 135 m2 please help

8 0

2 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Darina [25.2K]

Answer:

Given definite integral as a limit of Riemann sums is:

$\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Step-by-step explanation:

Given definite integral is:

$\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}$

Substituting (2) in above

$f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Riemann sum is:

$= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

4 0

2 years ago

-2(3y+5)=-4, find the value of 5y

Inessa05 [86]

Y=64 that's the answer to the problem

3 0

2 years ago

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