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3 years ago

GIVING BRAINLIEST!!! What’s 2 x2

Mathematics

2 answers:

Papessa [141]3 years ago

6 0

Answer:

Step-by-step explanation:

lutik1710 [3]3 years ago

3 0

Answer:

Step-by-step explanation:

2x2 is just 4 lol. I hope this helps lol

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A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

amm1812

Answer:

6546 students would need to be sampled.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

The dean randomly selects 200 students and finds that 118 of them are receiving financial aid.

This means that $n = 200, \pi = \frac{118}{200} = 0.59$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled?

n students would need to be sampled, and n is found when M = 0.01. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.645\sqrt{\frac{0.59*0.41}{n}}$

$0.01\sqrt{n} = 1.645\sqrt{0.59*0.41}$

$\sqrt{n} = \frac{1.645\sqrt{0.59*0.41}}{0.01}$

$(\sqrt{n})^2 = (\frac{1.645\sqrt{0.59*0.41}}{0.01})^2$

$n = 6545.9$

Rounding up:

6546 students would need to be sampled.

3 0

2 years ago

A large tank holds 1.9x10 to the power of 7 gallons of oil. how much oil can be stored in 7 tanks? Write in scientific notation

kupik [55]

It will equal 1.33x10^8

5 0

2 years ago

Determine if the columns of the matrix form a linearly independent set. Justify your answer. Choose the correct answer below. A.

kondaur [170]

Th matrix is missing. The matrix is :

$\begin{bmatrix}1 &-4 &4 \\ -4 &16 & 4 \end{bmatrix}$

Solution :

The column of the matrix are $\begin{bmatrix}1\\ -4\end{bmatrix}$ , $\begin{bmatrix}-4\\ 16\end{bmatrix}$ , $\begin{bmatrix}4\\ 4\end{bmatrix}$

Now each of them are vectors in $IR^2$ . But $IR^2$ has dimensions of 2. But there are 3 column vectors, hence they are linearly dependent.

Therefore, the column of the given matrix does not form the $\text{linearly independent set}$ as the set contains $\text{more vectors}$ than there are entries in each vector.