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3 years ago

5

100 points and brain list giving Help ASAP

1 answer:

sergij07 [2.7K]3 years ago

6 0

$-4x+60\geq84\qquad\text{subtract 60 from both sides}\\\\-4x\geq24\qquad\text{change the signs}\\\\4x\leq-24\qquad\text{divide both sides by 4}\\\\x\leq-6\to x\in(-\infty,\ -6]\\\\x-3$

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I need help with this question plzzz <br><br> Geometry

KATRIN_1 [288]

Answer:

If the perimeter of a square measures 32 cm, each side measures 32/4= 8 cm, because all sides are equal.
The diagonal that passes through the center of the square divides the square into two triangles. The triangles are formed by a <u>hypotenuse </u>(the diagonal, which is k in this case), <u>and two sides,</u> that measure 8 cm each, in this case.
Because of Pythagoras' theorem, we know that the <u>lenght of the hypotenuse</u> (in this case the hypotenuse is k) equals the squared root of the sum of the squared sides, which in this case can be expressed as $k=\sqrt{8^2+8^2} =\sqrt{64+64}=\sqrt{128}=11.31$ .
Then, k=11.31 cm.

3 0

3 years ago

Solve the equation for the variable numerically using a

tangare [24]

Answer:

x= 12

Step-by-step explanation

3x+8=44

subtract 8 from both sides: 3x+8= 44

-8 -8

3x=36

then divide by 3 on both sides

3x=36

3 3

which leaves : x=12

my explaining is horrible but i hope this helps

8 0

3 years ago

Help me for free brainlyist

WARRIOR [948]

Answer:

30. 5 and 6

31. about 7 feet

32. E

33. 7 and 8

34. 111

7 0

3 years ago

Laura borrowed $9,000 at 4% for 2 years. what was the total interest?

Nataly_w [17]

Answer:

$720

Step-by-step explanation:

I = Prt

I = (9000)(0.04)(2)

I = 720

6 0

3 years ago

Solve the following system of equations.<br> 2x+y=3<br> I= 2y - 1<br> x=<br> y=

marin [14]

<em>Note: I am assuming your second equation is:</em>

<em>x = 2y - 1</em>

<em></em>

Answer:

The solution to the system of equations is:

x = 1

y = 1

Step-by-step explanation:

Given the system of equations

2x+y=3

x = 2y - 1

solving the system of equations using the elimination method

$\begin{bmatrix}2x+y=3\\ x=2y-1\end{bmatrix}$

Arrange equation variables for elimination

$\begin{bmatrix}2x+y=3\\ x-2y=-1\end{bmatrix}$

Multiply x-2y=-1 by2: 2x-4y=-2

$\begin{bmatrix}2x+y=3\\ 2x-4y=-2\end{bmatrix}$

subtracting the equations

$2x-4y=-2$

$-$

$\underline{2x+y=3}$

$-5y=-5$

now solve -5y = -5 for y

$-5y=-5$

Divide both sides by -5

$\frac{-5y}{-5}=\frac{-5}{-5}$

Simplify

$y=1$

For 2x+y=3 plug in y=1

$2x+1=3$

subtract 1 from both sides

$2x+1-1=3-1$

Simplify

$2x=2$

Divide both sides by 2

$\frac{2x}{2}=\frac{2}{2}$

Simplify

$x=1$

Therefore, the solution to the system of equations is:

x = 1

y = 1

8 0

3 years ago