Answer:
The value is 
The correct option is a
Step-by-step explanation:
From the question we are told that
The margin of error is E = 0.05
From the question we are told the confidence level is 95% , hence the level of significance is

=> 
Generally from the normal distribution table the critical value of is

Generally since the sample proportion is not given we will assume it to be

Generally the sample size is mathematically represented as
![n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%7D%7BE%7D%20%5D%5E2%20%2A%20%5C%5E%20p%20%281%20-%20%5C%5E%20p%20%29%20)
=> ![n = [\frac{ 1.96 }{0.05} ]^2 *0.5 (1 - 0.5)](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7B%201.96%20%7D%7B0.05%7D%20%5D%5E2%20%2A0.5%20%281%20-%200.5%29%20)
=> 
Generally the margin of error is mathematically represented as

Generally if the level of confidence increases, the critical value of
increase and from the equation for margin of error we see the the critical value varies directly with the margin of error , hence the margin of error will increase also
So If the confidence level is increased, then the sample size would need to increase because a higher level of confidence increases the margin of error.
Following rules of logs, we can do the following:
log x^4 - log y^(1/2) + log z^3
Combine the first and 3rd factors to get log [x^4*z^3]
Seeing that the neg. sign signifies division, write this new term - log y^(1/2) as a quotient:
[x^4*z^3]
log ----------------
y^(1/2)
Next time, please include the instructions when you present your problem.
Thx.
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