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3 years ago

PLEASE HELP!! :( 6th grade math ( I suck at math)

Mathematics

2 answers:

ASHA 777 [7]3 years ago

5 0

Answer:

Width Length

5 8.7

7.9 11.6

9 12.7

11.3 15.0

13 16.7

Step-by-step explanation:

If they gave you the width, you add 3.7 to get the length.

If they gave you the length, you subtract 3.7 to get the width.

agasfer [191]3 years ago

4 0

Answer:

Width Length

5 8.7

7.9 11.6

9 12.7

11.3 15.0

13 16.7

Step-by-step explanation:

If they gave you the width, you add 3.7 to get the length.

If they gave you the length, you subtract 3.7 to get the width.

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5 in 9 in 10 in Surface Area =

yKpoI14uk [10]

5*9*10= Surface Area

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3 years ago

Three students performed a science experiment using salt and a beaker. The beaker contained 530.2 grams of salt before the exper

anzhelika [568]

We are subtracting 3 * 47.36 from 530.2

3 * 47.36 = 142.08

530.2 - 142.08 = 388.12

Your answer should be 388.12 grams left. Hope this helps!

3 0

3 years ago

Read 2 more answers

Will mark brainliest !!!

Wittaler [7]

Answer:

just mark points it is very easy

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3 years ago

A researcher wishes to be 95% confident that her estimate of the true proportion of individuals who travel overseas is within 3%

andre [41]

Answer: a) 683 b) 1067

Step-by-step explanation:

The confidence interval for population proportion is given by :-

$p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}$

a) Given : Significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}}=\pm1.96$

Margin of error : $E=0.03$

Formula to calculate the sample size needed for interval estimate of population proportion :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.2(0.8)(\dfrac{1.96}{0.03})^2=682.951111111\approx683$

Hence, the required sample size would be 683 .

b) If no estimate of the sample proportion is available then the formula to calculate sample size will be :-

$n=0.25(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.96}{0.03})^2=1067.11111111\approx1067$

Hence, the required sample size would be 1067 .

3 0

3 years ago

How many real number solutions does the equation y=2x^2−8x+8 have?

Dafna1 [17]

Answer:

1 real solution

Step-by-step explanation:

y=2x^2−8x+8

We can use the discriminant to determine the number of real solutions

b^2 -4ac

a =2 b = -8 c=8

(-8)^2 - 4(2)(8)

64 - 64

Since the discriminant is 0 there is 1 real solution

>0 there are 2 real solutions

< 0 two complex solutions

6 0

2 years ago