Answer:
600 m³
Step-by-step explanation:
Given:
- length of swimming pool = 30 m
- width of swimming pool = 10 m
- depth at deep end = 3 m
- depth at shallow end = 1 m
To find the volume of the water in the pool, find the area of a cross section (see attached image) and multiply it by the width of the pool.
<u>Area of cross section</u>
= area of rectangle - area of triangle
= (3 × 30) - [1/2 × 30 × (3 - 1)]
= 90 - 30
= 60 m²
<u>Volume of pool</u>
= area of cross section × width
= 60 × 10
= 600 m³
F(x)=2x^2-x-6
Factoring:
f(x)=2(2x^2-x-6)/2=(2^2x^2-2x-12)/2=[(2x)^2-(2x)-12]/2
f(x)=(2x-4)(2x+3)/2=(2x/2-4/2)(2x+3)→f(x)=(x-2)(2x+3)
g(x)=x^2-4
Factoring
g(x)=[sqrt(x^2)-sqrt(4)][sqrt(x^2)+sqrt(4)]
g(x)=(x-2)(x+2)
f(x)/g(x)=[(x-2)(2x+3)] / [(x-2)(x+2)
Simplifying:
f(x)/g(x)=(2x+3)/(x+2)
Answer: Third Option (2x+3)/(x+2)
Answer:
4^(-11)
Step-by-step explanation:
To divide powers, subtract the exponents.
4^(-2) / 4^9
-2-9=-11
So, the answer is 4^(-11), which is basically 4 to the eleventh power.
9514 1404 393
Answer:
$62.74
Step-by-step explanation:
The annuity formula can be used to find the payment needed. Fill in the known values and solve for the unknown.
The future balance due to a series of payments is given by ...
A = P(n/r)((1 +r/n)^(nt) -1)
where A is the account balance P is the payment made each period, n is the number of periods per year, r is the annual interest rate, and t is the number of years.
You have A = $20,000, r = 0.041, n = 12, t = 18 and you want to find P
P = A(r/n)/((1 +r/n)^(nt) -1)
P = $20,000(0.041/12)/((1 +0.041/12)^(12·18) -1) ≈ $62.74
A monthly payment of $62.74 is required.
