Answer:
3X+8 IS THE ANSWER FOR EQUATION
26 IS 2ND ANSWER
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Answer:
16 ft
Step-by-step explanation:
One of the other three sides is 12 ft. After that fence is subtracted from the total, there are 32 ft of fence left for the other two sides of the rectangle. That allows those sides to be 32 ft/2 = 16 ft long.
The rectangle can be 12 ft by 16 ft. The longer dimension is 16 ft.
Answer:
Jimmy; 26
Step-by-step explanation:
PEMDAS
Parentheses Exponents Multiplication Division Addition Subtraction
6 + 4 * 10 / 2 = 6 + 40 / 2
6 + 40 / 2 = 6 + 20
6 + 20 = 26
26
Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Answer:
25.13
Step-by-step explanation:
C=2πr=2·π·4≈25.13274cm