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Anit [1.1K]
3 years ago
10

Karl needs to build a stage that has an area of 72 square feet. The length of the stage should be longer than the width. What ar

e the possible whole number measurements for the length and width of the stage?
Mathematics
1 answer:
Goryan [66]3 years ago
3 0
Since the length is longer than the width, its a rectangle. The possible combinations are:
1 x 72 = 72
2 x 36 = 72
3 x 24 = 72
4 x 18 = 72
6 x 12 = 72
8 x 9 = 72
9 x 8 = 72
12 x 6 = 72
18 x 4 = 72
24 x 3 = 72
36 x 2 = 72
72 x 1 = 72
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kondor19780726 [428]

Answer:

3X+8 IS THE ANSWER FOR EQUATION

26 IS 2ND ANSWER

<u><em>Please mark as brainliest</em></u>

Have a great day, be safe and healthy

Thank u  

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4 0
3 years ago
Read 2 more answers
There is a 12-ft fence on one side of a rectangular garden. The gardener has 44 ft of fencing to the enclose the other three sid
Morgarella [4.7K]

Answer:

  16 ft

Step-by-step explanation:

One of the other three sides is 12 ft. After that fence is subtracted from the total, there are 32 ft of fence left for the other two sides of the rectangle. That allows those sides to be 32 ft/2 = 16 ft long.

The rectangle can be 12 ft by 16 ft. The longer dimension is 16 ft.

7 0
3 years ago
Four students simplify the expression below: 6 + 4 x 10 ÷ 2 Anshu's solution is 25 , David's solution is 46 , Jimmy's solution i
Mrac [35]

Answer:

Jimmy; 26

Step-by-step explanation:

PEMDAS

Parentheses Exponents Multiplication Division Addition Subtraction

6 + 4 * 10 / 2 = 6 + 40 / 2

6 + 40 / 2 = 6 + 20

6 + 20 = 26

26

7 0
2 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
3 years ago
I WILLL GIVE THE BRAINLEST!!!!
DedPeter [7]

Answer:

25.13

Step-by-step explanation:

C=2πr=2·π·4≈25.13274cm

4 0
3 years ago
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