The figure is made up of a cone and a cylinder.
Diameter = 16 ft
radius = 16÷2 = 8ft
Volume of the cone = 1/3bh
Volume of the cone =
Volume of the cone =
= 402.12
Volume of the cyclinder = bh
Volume of the cylinder =
Volume of the cylinder =
= 1206.37
Total = 402.12 + 1206.37 = 1608.49 cubic feet
Given, (0,−2).
Since the x-coordinate is 0, the point clearly lies on y-axis.
Also, the y-coordinate −2 being negative, the point lies on the negative y-axis.
We don't need the figure
angle b = 44 degrees
angle a = 62 degrees
angle e = 50 degrees
angle f = unknown
we know that
angle a + b + e + f = 180 degrees
50 + 44 + 62 + f =180 degrees
f= 180-50-44-62
but here there is only one blank so we have to add 44 and 62 to make one number that is 106
therefore, f = 180-50-106
if you further want to solve it angle f is 24
Answer:
h(x) = -16x² + 192x + 208
784ft
6 sec
13 sec
Step-by-step explanation:
a)
h(x) = -16x² +vx + h
here v represent velocity
represent initial height of launch
h(x) = -16x² + 192x + 208
b)
h(x) = -16x² + 192x + 208
here a = -16
b = 192
c = 208
x = -b/2a
= -192/2(-16)
= 6
plug this value in the equation
h(x) = -16(6)² + 192(6) + 208
= 784ft
e)
Plug h(x)=0 in the equation
0 = -16x² + 192x + 208
divide equation by -16
x² - 12x - 13 = 0
Factors
1x * -13x = -13
1x - 13x = -12
Factorised form
x² - 12x - 13 = 0
x² + x - 13x - 13 = 0
x(x+1) -13(x+1) = 0
(x+1)(x-13) = 0
x = -1
x = 13
Since time can not be negative so we will reject x = -1
Answer
given,
on first stop
number of car = 20 and number of trucks = 18
on second stop
number of car = 18 and number of trucks = 10
we need to calculate which rest stop has higher ratio of car to truck.
Rest Stop 1
ratio= r₁ =
r₁ =
r₁ =
Rest Stop 2
ratio= r₂ =
r₂ =
r₂=
hence, r₂ > r₁
rest stop 2 has more car to truck ratio than rest stop 1
