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Arada [10]
2 years ago
10

A cylinder is inscribed in a cube. If the edge of the cube is 3" long, find the volume of the cylinder.

Mathematics
2 answers:
Mazyrski [523]2 years ago
6 0

Answer:

The volume of cylinder is 21.21 units³.

Step-by-step explanation:

The side length of cube is 3 units.

If a cylinder is inscribed in that cube, then radius of the cylinder is 1.5 units and height of the cylinder is 3 units.

The volume of the cylinder is

V=\pi r^2h

The volume of cylinder is

V=\pi \times (1.5)^2\times (3)

V=21.20575

V\approx 21.21

Therefore the volume of cylinder is 21.21 units³.

maks197457 [2]2 years ago
4 0

Answer:

21.2 cubic inches

Step-by-step explanation:

Supposing that the diameter of the cylinder match with the longitude of the edge of the cube (see figure attached); then, cylinder's diameter (D) and height (h) are equal to 3 inches.

The volume of the cylinder (V) is calculated as follows:

V = π*(D^2)/4*h

V = π*(3^2)/4*3

V = 21.2 cubic inches

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No they are not equivalent

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What is 2160 minus 1600 long way
lilavasa [31]
Hey there, Lets solve this problem together. 

The First step is to line up the numbers. 

=  2160

- 1600 

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left} 

<span>We calculate </span>0-0<span>the result of which is </span>0<span> 
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<span>We calculate </span>6-0<span> the result of which is </span>6<span>.
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Since we get a negative number in the next column, we must take 1 from the next column and carry it over to this column. Now the number will be changed to 10.

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Therefore, 

2160 - 1600 = 0560 
8 0
2 years ago
A rectangle has an area of 12y^2+21y^512 y 2 +21y 5 12, y, squared, plus, 21, y, start superscript, 5, end superscript.The width
umka21 [38]

Answer:

<em>Width</em>: 3y²

<em>Length</em>: 4 + 7y³

Step-by-step explanation:

The area of the rectangle is the length multiplied by the width. For the area given: 12y² + 21y⁵

12y² = 3y²*4

21y⁵ = 3y²*7y³

So, the greatest common monomial factor is 3y², which is the width.

The area is 3y²*(4 + 7y³), the first term is the width, the other must be the length: 4 + 7y³.

8 0
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For brainliest and 100 points and no files or you will be reported and just to get points.
marshall27 [118]

Answer:

w=-\frac{3u}{2}+2

Step-by-step explanation:

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The swimming pool at Spring Valley High School is a rectangle with a width of 75 meters and a length of 35 meters. Around the pe
stealth61 [152]
Same as before

total=(2w+75)(2w+35)=4w²+220w+2625

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minus pool from total
4w²+220w+2625-2625=4w²+220w
4 0
2 years ago
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