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Sever21 [200]
3 years ago
12

Select the correct answer from each drop-down menu.

Mathematics
2 answers:
ASHA 777 [7]3 years ago
3 0

Answer:

trinomial

Step-by-step explanation:

ELEN [110]3 years ago
3 0

The first one is : quadratic.

The last one is :2

Step-by-step explanation:

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27 divided by 55 using long division (please show work) HELP
guapka [62]
27 divided by 55= 0.490909 repeating
Step by Step Explanation:
picture below

5 0
3 years ago
Pyramid A is a square pyramid with a base side length of 7 inches and a height of 6 inches. Pyramid B has a volume of 3,136 in?.
anygoal [31]

Answer:

WE HAVE FIND HOW MUCH MAY TIME BIGGER IS THE VOLUME OF PYRAMID B THAN PYRAMID A.

The answer is 32 times

Step-by-step explanation:

Volume of Pyramid B = 3136 in³

Volume of Pyramid A = ?

We have to find volume of Pyramid A. As Pyramid is a square pyramid, its volume is given as:

V=\frac{(b^2)(h)}{3}

where b = base = 7  and h = height = 6. Substitute the values:

V=\frac{7^2\cdot6}{3}\\V=98\\

Volume of Pyramid A = 98 in³

To find how many time B is bigger than A, divide volume of B by A:

\frac{3136}{98}=32

So, volume of Pyramid B is 32 times bigger than volume of Pyramid A

6 0
3 years ago
brainly is the best app in the whole world) sam has 5 dollars he works for 5 hours and he earns 900 dollars and hour how much mo
saveliy_v [14]

Answer:

Sam has $900 more money. In total he now has $905.

5 0
2 years ago
What is the slope of the linear equation 30x-60y=12
crimeas [40]

Answer:

60y = 30x - 12

y = 1/2x - 1/5

The slope is 1/2

5 0
3 years ago
Read 2 more answers
Use a truth table to show that P Qand (~PV Q) A (~QV P) are equivalen
kati45 [8]

Answer:  The given logical equivalence is proved below.

Step-by-step explanation:  We are given to use truth tables to show the following logical equivalence :

P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P)

We know that

two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.

The truth table is as follows :

P     Q      ∼P     ∼Q     P⇔ Q    ∼P ∨ Q     ∼Q ∨ P        (∼P ∨ Q)∧(∼Q ∨ P)

T     T         F        F             T            T                   T                       T

T     F         F        T             F             F                   T                       F

F     T         T        F             F            T                   F                       F

F     F         T        T             T            T                   T                       T

Since the corresponding truth vales for P ⇔ Q and (∼P ∨ Q)∧(∼Q ∨ P) are same, so the given propositions are logically equivalent.

Thus, P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P).

8 0
4 years ago
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