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3 years ago

Select the correct answer from each drop-down menu.

Mathematics

2 answers:

ASHA 777 [7]3 years ago

3 0

Answer:

trinomial

Step-by-step explanation:

ELEN [110]3 years ago

3 0

The first one is : quadratic.

The last one is :2

Step-by-step explanation:

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27 divided by 55 using long division (please show work) HELP

guapka [62]

27 divided by 55= 0.490909 repeating
Step by Step Explanation:
picture below

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3 years ago

Pyramid A is a square pyramid with a base side length of 7 inches and a height of 6 inches. Pyramid B has a volume of 3,136 in?.

anygoal [31]

Answer:

WE HAVE FIND HOW MUCH MAY TIME BIGGER IS THE VOLUME OF PYRAMID B THAN PYRAMID A.

The answer is 32 times

Step-by-step explanation:

Volume of Pyramid B = 3136 in³

Volume of Pyramid A = ?

We have to find volume of Pyramid A. As Pyramid is a square pyramid, its volume is given as:

$V=\frac{(b^2)(h)}{3}$

where b = base = 7 and h = height = 6. Substitute the values:

$V=\frac{7^2\cdot6}{3}\\V=98\\$

Volume of Pyramid A = 98 in³

To find how many time B is bigger than A, divide volume of B by A:

$\frac{3136}{98}=32$

So, volume of Pyramid B is 32 times bigger than volume of Pyramid A

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3 years ago

brainly is the best app in the whole world) sam has 5 dollars he works for 5 hours and he earns 900 dollars and hour how much mo

saveliy_v [14]

Answer:

Sam has $900 more money. In total he now has $905.

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2 years ago

What is the slope of the linear equation 30x-60y=12

crimeas [40]

Answer:

60y = 30x - 12

y = 1/2x - 1/5

The slope is 1/2

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3 years ago

Read 2 more answers

Use a truth table to show that P Qand (~PV Q) A (~QV P) are equivalen

kati45 [8]

Answer: The given logical equivalence is proved below.

Step-by-step explanation: We are given to use truth tables to show the following logical equivalence :

P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P)

We know that

two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.

The truth table is as follows :

P Q ∼P ∼Q P⇔ Q ∼P ∨ Q ∼Q ∨ P (∼P ∨ Q)∧(∼Q ∨ P)

T T F F T T T T

T F F T F F T F

F T T F F T F F

F F T T T T T T

Since the corresponding truth vales for P ⇔ Q and (∼P ∨ Q)∧(∼Q ∨ P) are same, so the given propositions are logically equivalent.

Thus, P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P).

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4 years ago