Question

In ΔOPQ, q = 2 cm, ∠O=59° and ∠P=55°. Find the length of p, to the nearest 10th of a centimeter.

Answer 1

Answer:

1.8 cm

Step-by-step explanation:

User the law of Sines.

$\frac{p}{sin(P)} = \frac{q}{sin(Q)} \\\\\\p= \frac{q*sin(P)}{sin(Q)}$

Q = 180 - ∠O - ∠P = 180-59-55=66

Plug in the numbers using the calculator and get 1.7933470905822447027008654200424‬

Now you need to round it, and you get 1.8 cm