All categories

2 years ago

Whoever knows how to solve this please help!

Mathematics

1 answer:

sweet [91]2 years ago

7 0

Answer:

418ft²

Step-by-step explanation:

Find the surface area of both triangle shaped sides.

8 * 12 = 96

96 / 2 = 48 (surface area of one triangular side)

48 * 2 = 96

Find the surface area of both square shaped sides.

10 * 10 = 100

100 * 2 = 200

Find the surface area of the rectangular base side.

12 * 10 = 120

Add everything together.

96 + 200 + 120 = 418

Best of Luck!

You might be interested in

If a || b and _____, then a || c.

OLEGan [10]

<h2>Hello!</h2>

The answer is:

The correct option, is the second option:

b || c ( b and c are parallel).

To solve the problem, let's remember the following relationship:

If:

$a=b$

and

$b=c$

Then:

$a=c$

So, from the statement we know that a and b are parallel (a || b), so, if a and c are parallel ( a || c) it means that b and c are parallel ( b || c).

Hence, the correct option is:

The second option, b || c ( b and c are parallel)

Have a nice day!

7 0

3 years ago

3/5 of a fence was installed in 1 1/2 days. how many days to install the whole fence?

Andreyy89

First, let's convert the mixed number 1 1/2 to the improper fraction 3/2. We're given that it takes 3/2 days to install 3/5 of a fence. We're looking for how long it takes to install one whole fence - or 5/5 of a fence. To determine that, let's first find out how long it takes to install <em>1/5 of a fence</em>, and then multiply that quantity by 5 to obtain our answer.

If it takes 3/2 days (3 half-days) to install 3/5 of a fence (3 fifths of a fence), then it makes sense that it would take <em>1/2 </em><em>day</em> (<em>1 </em>half-day) to install <em>1/5</em> of a fence (<em>1 </em>fifth of a fence).

If it takes 1/2 day to install 1/5 of a fence, then it should take 5 times that amount of time to install all 5/5 of it, or 5 * (1/2) = 5/2 days, or 2 1/2 days as a mixed number.

7 0

3 years ago

Read 2 more answers

Mark ran 4 3/4 miles on Monday and 2 1/5 miles on Tuesday.

Phoenix [80]

139 mi 1 km 139 km
--------- * ---------- = -------------- = 11.2 km
20 0.62 mi 12.4

4 0

3 years ago

If this particular arithmetic sequence, a7=34 and a15=74. What is the value of a21

Ilya [14]

This is an arithmetic sequence, meaning, to get the next term, you simply add some value to the current one, namely the "common difference" "d".

now, we know the 17th term is 34, let's go to the 15term then

34 + d
34 + d + d
34 + d + d + d
34 + d + d + d + d
34 + d + d + d + d + d
34 + d + d + d + d + d + d
34 + d + d + d + d + d + d + d
34 + d + d + d + d + d + d + d + d

now, notice, we got to the 15th term, which is 34 + d + d + d + d + d + d + d + d, or namely 34 + 8d, it just so happen we know is 74, therefore,

$\bf 34+8d=74\implies 8d=40\implies d=\cfrac{40}{8}\implies \boxed{d=5}$

ok, now that we know what the common difference is, let's find the first term in the sequence using the 7th term of 34,

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=7\\
d=5\\
a_7=34
\end{cases}
\\\\\\
a_7=a_1+(7-1)5\implies 34=a_1+(7-1)5
\\\\\\
34=a_1+30\implies \boxed{4=a_1}$

and now let's use those 2 found folks, to get the 21st term,

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=4\\
d=5\\
n=21
\end{cases}
\\\\\\
a_{21}=4+(21-1)5\implies a_{21}=4+100\implies a_{21}=104$

3 0

2 years ago

What is the approximate volume of a cone with a height of 12 in and radius of 9 in ? Use 3 14 to approximate pi, and express you

Rama09 [41]

Answer:

1017.36

Step-by-step explanation: The formula for cone volume is 3.14(r^2)(h/3). Plug in all of your values to get the answer.

3 0

3 years ago

Whoever knows how to solve this please help!​

Whoever knows how to solve this please help!