Answer:
ΔRMS ≅ ΔRQS by AAS
Step-by-step explanation:
See the diagram attached.
Given that ∠ RMS = ∠ RQS and N is any point on RS and ∠ MRS = ∠ SRQ.
Therefore, between Δ RMS and Δ RQS, we have
(i) ∠ RMS = ∠ RQS {Given}
(ii) ∠ MRS = ∠ SRQ {Also given} and
(iii) RS is the common side.
So, by angle-angle-side i.e. AAS criteria we can write ΔRMS ≅ ΔRQS. (Answer)
Answer:
7. cos(X) = 3/5 = 0.6
cos(Y) = 4/5 = 0.8
8. cos(X) = 15/17 ≈ 0.8824
cos(Y) = 8/17 ≈ 0.4706
9. cos(X) = 1/2 = 0.5
cos(Y) = (√3)/2 ≈ 0.8660
Step-by-step explanation:
The trigonometric ratio for cosine is given as follows;
7. The adjacent leg length to ∠X = 27
The length of the hypotenuse side of the triangle = 45
∴ cos(X) = 27/45 = 3/5 = 0.6
Cos(X) = 3/5 = 0.6
The adjacent leg length to ∠Y = 36
∴ cos(Y) = 36/45 = 4/5 = 0.8
cos(Y) = 4/5 = 0.8
8. The adjacent leg length to ∠X = 15
The length of the hypotenuse side of the triangle = 17
∴ cos(X) = 15/17 ≈ 0.8824
The adjacent leg length to ∠Y = 8
∴ cos(Y) = 8/17 ≈ 0.4706
9. The adjacent leg length to ∠X = 13
The length of the hypotenuse side of the triangle = 26
∴ cos(X) = 13/26 = 1/2 = 0.5
Cos(X) = 1/2 = 0.5
The adjacent leg length to ∠Y = 13·√3
∴ cos(Y) = 13·√3/26 = (√3)/2 ≈ 0.8660
cos(Y) = (√3)/2 ≈ 0.8660.