Solutions
1) Find the least common denominator of 7/10 and 1/5.
10: 10
5 : 5 , 10
The least common denominator is 10.
2) Make the denominator of 1/5 to 10. Multiply numerator and denominator by 2.
1 x 2 = 2
5 x 2 = 10
3) New fraction
7/10 + 2/10
4) Add
7+2 = 9
9/10 is answer
9/10 can not be simplified. It is already in reduced form.
Answer:
Step-by-step explanation:
Given the inequality
|x|> 1
The modulus of x shows that x can be both positive and negative value.
If x is positive:
x>1
1<x
If x is negative:
-x>1
Multiplying both sides of the inequality by minus will change the inequality sign
x < -1
Combining both inequalities:
1<x<-1
Find the position on the number line in the attachment
Answer:
41235
Step-by-step explanation:
There are 120 five-digit numbers that can be made from the digits 1, 2, 3, 4, 5 if each digit is used once in the number,
The total number of times where each number will occur or be at first place is calculated as:
4! = 4 × 3 × 2 × 1
= 24
Hence,
24th number = The last number where 1 is at first place
We can write this out as:
12345
12354
12435
12453
12534
12543
13245
13254
13425
13452
13524
13542 e.t.c.
48th number = The last number where 2 is at first place
72nd place = The last number where 3 is at first place.
This means, the 73rd number is the first number where 4 is at first place.
Therefore, the 73rd number based on pattern is 41235
Answer:
The Falcones have to travel at 25 m/h to make the trip in 2 hours.
Step-by-step explanation:
In order to find the answer you have to use the formula to calculate speed:
speed=distance/time
distance=50 miles. The stament indicates that the distance between Syracuse and Buffalo is 1 inch and that the map has a scale of inch = 50 miles.
time=2 hours
Now, you can replace the values on the formula:
speed=50 miles/2 hours
speed=25 m/h
According to this, the answer is that the Falcones have to travel at 25 m/h to make the trip in 2 hours.

Let
, so that
:

Now the ODE is separable, and we have

Integrating both sides gives

For the integral on the left, rewrite the integrand as

Then

and so


Given that
, we find

so that the particular solution to this IVP is
