Answer:
CH₄N
Explanation:
Given that;
mass of the sample = 0.312 g
mass of CO2 = 0.458 g
mass of H2O = 0.374 g
nitrogen content of a 0.486 gg sample is converted to 0.226 gg N2N2.
Let start with calculating the respective numbers of moles of Carbon Hydrogen and Nitrogen from the given data.
numbers of moles of Carbon from CO2 = 
= 
= 0.0104 mole
numbers of moles of hydrogen from H2O = 
= 
= 0.02077 × 2
= 0.0415 mole
The nitrogen content of a 0.486 g sample is converted to 0.226 g N2
Now, in 1 g of the sample; The nitrogen content = 
in 0.312 g of the sample, the nitrogen content will be; 
= 0.1450 g of N2
number of moles of N2 = 
= 
= 0.0103 mole
Finally to determine the empirical formula of Carbon Hydrogen and Nitrogen; we have:
Carbon Hydrogen Nitrogen
number of moles 0.0104 0.0415 0.0103
divided by the
smallest number

of moles
1 : 4 : 1
∴ The empirical formula = CH₄N