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3 years ago

Homogeneous mixture that does not settle out upon standing reflect light is an element. solid. hydrated.

1 answer:

andrey2020 [161]3 years ago

5 0

Homogeneous mixture that does not settle out upon standing but which will reflect light is called COLLOIDS.
There are three types of homogeneous mixtures, these are: solutions, colloids and suspension. Colloids are usually distinguished by Tyndall effects. Light passing through a colloidal dispersion will be reflected.<span />

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Prandtl number in heat transfer analogues to which dimension less number in mass transfer. a) Schmidt number b) Sherwood number

Cloud [144]

Answer:

a) Schmidt number

Explanation:

Prandtl number in heat transfer is analogues to Schmidt number in mass transfer.

Prandtl number in heat transfer is the ration of momentum diffusivity to the heat diffusivity.

$P_r = \frac{\nu}{\alpha}$

Whereas, Schmidt number in mass transfer is the ratio of momentum diffusivity to the mass diffusivity.

$S_c= \frac{\nu}{\nu_{AB}}$

5 0

3 years ago

If the thermal energy of the system increases by 400 j and 1100 j of heat were added to the system how much work did the system

Pie

your answer should be 700J

7 0

3 years ago

Are the following solutions acidic, basic, ot neutral.

Slav-nsk [51]

Answer:

1) Basic

2) Basic

3) Acidic

Explanation:

pH of a solution is a measure of the H3O+ ions in the solution and hence reflects its acidity.

$pH = -log[H3O+]$

Solutions are classified as acidic, basic or neutral based on the pH range

-pH < 7, acidic

- pH = 7, neutral

- pH > 7, basic

1) [H3O+] = 2.5*10^-9M

$pH = -log[H3O+]=-log[2.5*10^{-9}]=8.60$

Since pH > 7, solution is basic

2)[OH-] = 1.6*10^-2M

$pOH = -log[OH-]=-log[1.6*10^{-2}]=1.80$

pH = 14 - pOH = 14 - 1.80 =12.2

Since pH > 7, solution is basic

3) [H3O+] = 7.9*10^-3M

$pH = -log[H3O+]=-log[7.9*10^{-3}]=2.10$

Since pH < 7, solution is acidic

6 0

3 years ago

If the [H+] in a solution is 1 × 10–1 mol/L, what is the [OH–]? Show your work.

AVprozaik [17]

Hello!

The basic equations to solve this is
pH = -log[H+]
pOH = -log[OH-]
pH + pOH = 14
------------------------------------------------------------------------------------------------------
Find pH

pH = -log(1 * 10^-1)
pH = 1
------------------------------------------------------------------------------------------------------
Find pOH
1 + pOH = 14

pOH = 13
------------------------------------------------------------------------------------------------------
Find OH-
[OH-] = 10^(-pOH)
[OH-] = 1 * 10^-13mo/L

The answer is $[OH-] = 1 * 10^{-13} mol/L$

Hope this helps!

3 0

3 years ago

What is the molarity of a NaOH solution if 32.47 mL is required to titrate 0.6013 g of potassium hydrogen phthalate (C8H5O4K)

Artist 52 [7]

Answer:

0.0907 M

Explanation:

Before you can calculate the molarity, you need to convert grams to moles (via molar mass) and convert mL to L.

(Step 1)

Molar Mass (C₈H₅O₄K):

8(12.011 g/mol) + 5(1.008 g/mol) + 4(15.998 g/mol) + 39.098 g/mol

Molar Mass (C₈H₅O₄K): 204.218 g/mol

0.6013 g C₈H₅O₄K 1 mole
------------------------------ x ------------------ = 0.00294 moles C₈H₅O₄K
204.218 g

(Step 2)

1,000 mL = 1 L

32.47 mL 1 L
--------------- x ----------------- = 0.03247 L
1,000 mL

(Step 3)

Molarity (M) = moles / volume (L)

Molarity = 0.00294 moles / 0.03247 L

Molarity = 0.0907 M

6 0

2 years ago