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3 years ago

How would 6 3/6 be classified

Mathematics

2 answers:

gulaghasi [49]3 years ago

4 0

If it's math then 6 3/6 would be a mixed number

Zinaida [17]3 years ago

4 0

Rational and real,. b is your answer for sure

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1. Solve the given equation on the domain [0,2pi]

Mekhanik [1.2K]

Answer:

1.x = pi/3 or 4pi/3

2. x = -pi/6 +2pi*n or 5pi/6 + 2pi *n where n is an integer

Step-by-step explanation:

1. sqrt(3) tan x = 3

Divide each side by sqrt(3)

sqrt(3)/sqrt(3) tan x = 3/sqrt(3)

tan x = sqrt(3) * sqrt(3)/sqrt(3)

tan x = sqrt(3)

Take the inverse of each side

arctan (tanx) = arctan (sqrt(3))

x = arctan (sqrt(3))

x =pi/3 or - 2pi/3

Since the domain is between 0 and 2pi, add 2pi to - 2pi/3 since the trig functions are circular

x = pi/3 or -2pi/3 + 6pi/3

x = pi/3 or 4pi/3

2. 3 tan x = -sqrt(3)

Divide each side by 3

3/3 tan x = -sqrt(3)/3

tan x = -sqrt(3)/3

Take the arctan of each side

arctan (tan x) = arctan ( -sqrt(3)/3)

x = arctan ( -sqrt(3)/3)

x =-pi/6 or 5pi/6

We want all values for x so add 2pi*n to each value where n is an integer

x = -pi/6 +2pi*n or 5pi/6 + 2pi *n where n is an integer

6 0

3 years ago

Something dive (-9) = 6

Nataly_w [17]

Answer:

-3

Step-by-step explanation:

idk im just guessing

5 0

4 years ago

What's the sum of 3/8 and 1/16? a. 1/6 b. 7/16 c. 4/24 d. 1/4

Norma-Jean [14]

Answer: B

Step-by-step explanation: 3/8 + 1/16 = 0.4375 and 7/16 = 0.4375

7 0

2 years ago

Read 2 more answers

URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

5 0

3 years ago

On,Saturday, Alexa babysat her neighbors kids for 180 minutes. Then, on Sunday she babysat her little brother for 2 hours.how ma

patriot [66]

Answer:

5 hours

Step-by-step explanation:

To change minutes to hours you will have to divide the total minutes by 60 (because 60 minutes is in one hour), in this situation it would look like this:

180/60 = 3

So, Alexa babysat for 3 hours on Saturday.

Now, just add the 3 hours from Saturday and 2 hours from Sunday and you get a total of 5 hours!

<em>I hope this helps!!</em>

8 0

3 years ago