Csc x · sec x - tan x =
= 1 / sin x · 1 / cos x - sin x / cos x =
= 1 / sinx cos x - sin² x / sin x cos x =
= ( 1 - sin² x ) / (sin x cos x) =
= cos² x / ( sin x cos x ) =
= cos x / sin x = cot x
Answer:
Step-by-step explanation:
1) m∠1 +m∠2 + m∠3 = m∠LAM (Angle addition postulate)
2) m∠1 + m∠2 + m∠3 = 180 (def. of straight angle)
3) y║z (Given)
4) ∠1 ≅ ∠5 (alternate interior angles theorem)
5) ∠3 ≅ ∠6 (alternate interior angles theorem)
6) Since m∠1 + m∠2 + m∠3 = 180
m∠5 + m∠2 + m∠6 = 180
Hence proved.
Answer:
<h2>124.1m</h2>
Step-by-step explanation:
29.4 per sec > Building 80m
Height = S = 4.9t^2 + 29.4t + 80
Solve for t:
t = 1.24 (approximately)
If t needed coordinates / solve using the quadratic formula:
t = (1.24 , -7.24)
<h3>The ball's maximum height is 124.1 meters.</h3>
they are all quadrilateral s
hope this helps ;)
