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lianna [129]
3 years ago
13

What is the value of x in the equation 8 + 4 = 2 (x minus 1)?

Mathematics
2 answers:
Tanzania [10]3 years ago
6 0

Answer:

x = 7

Explanation:

8 + 4 = 2 (x − 1)

Simplify both sides of the equation

8 + 4 = 2(x − 1)

8 + 4 = (2)(x) + (2)(−1) (Distribute)

8 + 4 = 2x + −2

(8 + 4) = 2x − 2 (Combine Like Terms)

12 = 2x − 2

12 = 2x − 2

Flip the equation

2x − 2 = 12

Add 2 to both sides

2x − 2 + 2 = 12 + 2

2x = 14

Divide both sides by 2

2x  / 2 = 14 / 2

x = 7

givi [52]3 years ago
3 0

Answer:

7

Step-by-step explanation:

8+4 = 2(x-1)

12 = 2(x-1)

6 = x-1

x = 7

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Solve the equation.<br> a² = 100<br> Enter the correct answer in the boxes.<br> a = 10 or a = ?
Lyrx [107]
A = 10 or a = -10

When you square a number, you're essentially multiplying it by itself.

Recall that multiplying two negative numbers will result in a positive numbers. Knowing this, we know that -10 times -10 equals 100.
7 0
3 years ago
4x + 2y =10<br><br> 4x -2y = -10<br> perpednicular or paralell
Alina [70]

Answer:

the answer is perpendicular I think :)

6 0
3 years ago
How many real number solutions does the equation have
Ksju [112]
You have to find the discriminat b^2 -4ac

If it is > 0, the function has two real solutions
if it is = 0, the function has one real solution
if it is <0, the function has no real solution

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Answer c. no solution
5 0
3 years ago
What is the area of the composite figure? (6π 4) cm2 (6π 16) cm2 (12π 4) cm2 (12π 16) cm2
raketka [301]

The area of the considered composite figure is given by: Option: 6π + 16 cm²

<h3>How to calculate the surface area of a composite figure?</h3>

Surface area are derived for some standard shapes like circle, triangle, parallelogram, rectangle, trapezoid, etc.

When some shape comes which isn't standard figure, then we find its area by slicing it (virtually, like by drawing lines) in standard shapes. Then we calculate those composing shapes' area and sum them all.

Thus, we have:

\text{Area of composite figure} = \sum (\text{Area of composing figures})

That ∑ sign shows "sum"

For this case, the missing image is attached below.

As visible, the area of the figure = Sum of area of those 3 semi circles + Area of that square(its square because it has 4 equal sides in which adjacent sides are perpendicular) in between.

The side of the square is of 2+2=4 cm( as half of its side is 2 cm), thus, Area of that square = 4² = 16 cm²

All those 3 semicircles has radius = 2 cm

Since radius is same, so area of those 3 semicircle is same = \dfrac{\pi r^2}{2} = \dfrac{\pi (2)^2}{2} = 2 \pi\: \rm cm^2

Thus, we get:

Area of the composite figure = 2 \pi +2 \pi +2 \pi  + 16 \: \rm cm^2 = 6 \pi+ 16 \: \rm cm^2

Learn more about area of a composite figure here:

brainly.com/question/10254615

6 0
3 years ago
Which of the following represents a Type I error for the null and alternative hypotheses H0:μ≤$3,200 and Ha:μ&gt;$3,200, where μ
Nuetrik [128]

Answer:

Option a) Type I error would occur if we reject null hypothesis and conclude that the average amount is greater than $3,200 when in fact the average amount is $3,200 or less.        

Step-by-step explanation:

We are given the following information in the question:

H_{0}: \mu \leq \$3,200\\H_A: \mu > \$3,200

where μ is the average amount of money in a savings account for a person aged 30 to 40.

Type I error:

  • Type I error is also known as a “false positive” and is the error of rejecting a null  hypothesis when it is actually true.
  • In other words, this is the error of accepting an  alternative hypothesis when the results can be  attributed by null hypothesis.
  • A type I error occurs during the hypothesis testing process when a null hypothesis is rejected, even though it is correct and should not be rejected.

Thus, in the above hypothesis type  error will occur when we reject the null hypothesis even when it is true.

Option a) Type I error would occur if we reject null hypothesis and conclude that the average amount is greater than $3,200 when in fact the average amount is $3,200 or less.

3 0
3 years ago
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