Answer:
Relationship between compound interest and exponential growth
C.I = ![P[(1 + \frac{R}{100})^{n} - 1]](https://tex.z-dn.net/?f=P%5B%281%20%2B%20%5Cfrac%7BR%7D%7B100%7D%29%5E%7Bn%7D%20-%201%5D)
where, P =Principal
R =Rate of interest, n= Duration i.e time interval for which money has been taken, C.I =Compound Interest
Exponential growth = A 
Where , A=Initial value of population, K= Rate at which population is declining in percentage, s=total time between starting population and final population
Now , If you compare between Exponential growth and compound interest
P→(Replaced by)→A,
R→(Replaced by)→K,
n→(Replaced by)→s,
As C.I is calculated for money, and Exponential word is used for both money as well as increase in population.
So, just replacing keeping the meaning same
C.I =
- P
→Compound Interest = Exponential growth - Initial Value(either money or any population considered)
Answer:
It actually doesnt factor!
Step-by-step explanation:
Answer:
120m^2
Step-by-step explanation:
8 x 12= 96
6 x 8= 48
48/2= 24
24+96= 120m^2
<u><em>Answer:</em></u>

<u><em>Explanation:</em></u>
We know that the initial value of a function is the output of the function when the input is zero.
In other words, it is the value of f(x) when x = 0
<u>Now, checking the given table, we can find that:</u>
at x = 0 ...............> f(x) = 
<u>This means that</u> the output is
when the input is zero which means that our initial value is 
Hope this helps :)