Simply divide the 8 cars by the numerator of the fraction 4 to get your answer!
The slope-intercept form of an equation of a line:
m - slope
b - y-intercept
We have the equations in the standard form. Convert to the slope-intercept form:
<em>subtract 3x from both sides</em>
<em>add x to both sides</em>
<em>divide both sides by 3</em>
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We need only two points to plot a graph of each function.
for x = 0 and for x = -3:
for x = 0 and for x = -3:
Look at the picture.
2. Create frequency tables to represent the morning and afternoon dogs as two sets of data. Group the weights into classes that range 10 pounds. (4 points: 2 points for appropriate intervals, 2 points for correctly portraying data)
Morning
Range
Dogs
10 to 19
3
20 to 29
4
30 to 39
3
Afternoon
Range
Dogs
0 to 9
2
10 to 19
3
20 to 29
1
30 to 39
2
40 to 49
1
50 to 59
1
3. What is the median of the morning (AM) group? What is the median of the afternoon (PM) group? (2 points: 1 point for each answer)
Morning (AM): 25.5
Afternoon (PM): 19
4. What is the first quartile (Q1) of the morning (AM) group? What is the first quartile (Q1) of the afternoon (PM) group? (2 points: 1 point for each answer)
Morning (AM): 10
Afternoon (PM): 0
5. What is the third quartile (Q3) of the morning (AM) group? What is the third quartile (Q3) of the afternoon (PM) group? (2 points: 1 point for each answer)
Morning (AM): 20
Afternoon (PM): 10
6. What is the interquartile range (IQR) of the morning (AM) group? What is the interquartile range (IQR) of the afternoon (PM) group? (2 points: 1 point for each answer)
Morning (AM): 39
Afternoon (PM): 29
7. The average weights of the dogs are the same for the morning and afternoon groups. But based on your comparative box plot and the IQRs of the two groups, which group of dogs does you think would be easier to walk as one group? Why? (2 points: 1 point for the answer, 1 point for justification)
The morning dogs, there are fewer dogs and they seem to weigh less.
All of the answers I have here!
Answer:
The diameter is 6.92 unit.
Step-by-step explanation:
Given : An equilateral triangle with sides of length 6 is inscribed in a circle.
To find : What is the diameter of the Circle?
Solution :
First we picture the situation.
Refer the attached figure below.
We that the angles of equilateral triangle is 60 degrees.
Then, we divide the triangle into two parts to solve the radius.
As,
∠ACD is 60°
In triangle OCD,
Diameter = 2r=2(3.4641)=6.92 unit.
Therefore, The diameter is 6.92 unit.
Place (3x + 1)/12, and (4x)/15 (Note: the bottom triangle's base is 12 + 3)
Set the two equal to each other
(3x + 1)/12 = (4x)/15
Cross multiply
15(3x +1)/12(12) = 12(4x)/15(15)
15(3x + 1) = 12(4x)
Distribute the 15 to the two terms in the parenthesis, and 12 to 4x
15(3x) = 45x
15(1) = 15
12(4x) = 48x
45x + 15 = 48x
Isolate the variable, subtract 45x from both sides
45x (-45x) + 15 = 48x (-45x)
15 = 48x - 45x
Simplify
15 = 3x
Isolate the x, divide 3 from both sides
15/3 = 3x/3
x = 15/3
x = 5
5 is your answer
hope this helps
