Answer:
4-
-
Step-by-step explanation:
Answer:
(8.213 ; 8.247)
Step-by-step explanation:
Given the data :
No. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Dia. 8.23 8.16 8.23 8.25 8.26 8.23 8.20 8.26 8.19 8.23 8.20 8.28 8.24 8.25 8.24
Sanple size, n = 15
Sample mean, xbar = Σx / n = 123.45 / 15 = 8.23
The sample standard deviation, s = √(x -xbar)²/n-1
Using calculator :
Sample standard deviation, s = 0.03116
s = 0.031 (3 decimal places)
The 95% confidence interval :
C.I = xbar ± (Tcritical * s/√n)
Tcritical at 95%, df = 15 - 1 = 14
Tcritical = 2.145
C.I = 8.23 ± (2.145 * 0.031/√15)
C.I = 8.23 ± 0.0171689
C.I = (8.213 ; 8.247)
The is it mean, range, mode, or median of the following set of data is 6. 13, 7, 9, 5, 2, 3, 5, 4, 10, 12
grandymaker [24]
the way you have laid this question out is strange but im assuming you want me to find the mean, range, medium and mode of the numbers provided?
<h2>
Answer:</h2>
median=order them and find the middle= <u><em>6</em></u>
mean=add them all up and divide by the amount of numbers=(6+13+7+9+5+3+2+5+4+10+12)/11=<em><u>6.9</u></em>
range= the difference between the smallest and largest number=13-2=<u><em>11</em></u>
mode= the one that appears the most= <em><u>5</u></em>
