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melomori [17]
3 years ago
14

Find the area of the given figure and please put all the steps you made as well

Mathematics
1 answer:
mylen [45]3 years ago
3 0

Answer:

B. 196.5

Step-by-step explanation:

First lets fine the semi circle's area.

The area of an circle is πr², so in order to find half of a circle, simply divide the answer by 2.

The diameter of the circle is 16, and the radius is half of 16, and which the radius will be 8. Now simply plug in 8 into the formula, and substitute π with 3.14

(3.14)(8)²=200.96 and half of that is 100.48

The area of the semi-circle is 100.48, and now it's time to find the area of the triangle.

The formula for area of an triangle is A=1/2bh

We can see that the base is 16 and height is 12, and now plug it in.

A=1/2(16)(12)= 96.

The area of the triangle is 96 and the area of the semi-circle is 100.48, when they are added, it is 196.48. When it is rounded, the answer is 196.5. And so the answer is B.

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3 years ago
5/8 of 3/7 is ...<br><br> What is the ...
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15/56

Step-by-step explanation:

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3 0
3 years ago
What is the ratio of the outputs for x = 6 and x = 2?
Talja [164]
Number 6 4 is the answer
5 0
3 years ago
Is 0.6 repeating a rational number
julsineya [31]
Any decimal number that is repeating can be written in the form <span>\frac{a}{b}</span> with b not equal to zero, so they are rational numbers.

The short answer is yes, 0.6 repeating is a rational number.

Hope this helped :)
6 0
3 years ago
It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0
3 years ago
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