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aev [14]
2 years ago
12

It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando

mly selected throughout the country, the selections for each chain being independent. The following hourly rates are recorded:
Chain A 4.25 4.75 3.80 4.50 3.90 5.00 4.00 3.80
Chain B 4.60 4.65 3.85 4.00 4.80 4.00 4.50 3.65
Under the assumption of normality and equal variances, can it be concluded at the 5% significance level that chain A pays more than chain B for the job under consideration?
Mathematics
1 answer:
notka56 [123]2 years ago
3 0

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

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3 years from now, Ron's age will be 2 times that of Miley. Three years ago, Ron's age was 3 times that of Miley.
andrezito [222]

Answer:

M=9

EXPLANATION:

Let R represent Ronald’s present age. Let M represent Miley’s present age. Three years from now, Ronald and Miley will be R+3 and M+3 years old, respectively.

Your assertion “Three years from now, Ron’s age will be 2 times that of Miley's” can be written as

R + 3 = 2*(M + 3)

Similarly, your assertion “Three years ago, Ron's age was 3 times that of Miley's” can be written as

R - 3 = 3*(M-3)

We can add the left side of these equations together, and also the right side of these equations together, and obtain a new equation …

R + 3 + R - 3 = 2*(M + 3) + 3*(M - 3) = 2M + 6 + 3M - 9 = 5M - 3

This can be simplified to

2R = 5M - 3

We can divide both sides of the last equation by 2, and obtain ..

(2/2) * R = (5/2) * M - 3/2, or R = (5/2) * M - 3/2.

Now we can “plug in” the last equation into either of our first two equations of this post, and solve for M.

Using the first equation, we have

(5/2) * M - 3/2 + 3 = 2 *(M + 3) = 2M + 6

We now have

(5/2) * M + 3/2 = 2M + 6

The left side of this equation can be rewritten as

(5M + 3) / 2, so we obtain

(5M + 3) / 2 = 2M + 6

Multiplying both sides by 2, we have

5M + 3 = 4M + 12

Subtracting 4M and 3 from both sides, we obtain

M = 9

Miley’s present age is 9.

plss give brainliest

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Answer:11

Step-by-step explanation:

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Kaylis [27]

Answer:

A= (0,0) and B = (6,3)

We can find the length AB with the following formula:

d = \sqrt{(x_B -x_A)^2 +(y_B -y_A)^2}

And replacing we got:

d = \sqrt{(6-0)^2 +(3-0)^2} = \sqrt{45}= 3\sqrt{5}

So then the length AB would be 3\sqrt{5}

Step-by-step explanation:

For this case we have the following two points:

A= (0,0) and B = (6,3)

We can find the length AB with the following formula:

d = \sqrt{(x_B -x_A)^2 +(y_B -y_A)^2}

And replacing we got:

d = \sqrt{(6-0)^2 +(3-0)^2} = \sqrt{45}= 3\sqrt{5}

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=53192-2616

=50576

=5.1×10⁴

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