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eimsori [14]
3 years ago
13

It costs $26 to join Gym X, plus an additional $33 per month. It

Mathematics
1 answer:
stellarik [79]3 years ago
6 0

Answer:

11 months

26+33(11)=389

59+30(11)=389

The 11 is in going for x and represents the months.

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Question 20 (5 points)
igor_vitrenko [27]

Answer:

Step-by-step explanation:

What you gave 4x – y = 7 is in standard form

The problem on screen

4x-2/3y=7

The standard form is 12x-2y=21

Answer is A

3 0
2 years ago
Skyler bought a hover board on sale for $300. She purchased the hover board on a day the offering was 40% off. What was the orig
zvonat [6]
300       40
------ =  -------
  x         100




30000=40x

x=750.

The original price was $750





4 0
2 years ago
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What is the solution to the equation 3/5n - 4/5 = 1/5n?
antiseptic1488 [7]

Answer: 2

Step-by-step explanation:

3 0
3 years ago
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Which value is closets to 8 11/20 A)8 B)8 1/2 C)8 3/4 D) 9
Alona [7]
I would say the answer is B. 8 1/2 because 11/20 is close to 10/20 which would be the same as 1/2
4 0
3 years ago
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. Whe
podryga [215]

Answer:

The value  is  n = 384

The correct option is a

Step-by-step explanation:

From the question we are told that

   The margin of error is  E =  0.05

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally since the sample proportion is not given we will assume it to be

      \^ p = 0.5

Generally the sample size is mathematically represented as  

    n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>   n = [\frac{ 1.96 }{0.05} ]^2 *0.5 (1 - 0.5)

=>   n = 384

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

Generally if the level of confidence increases,  the critical value of  \frac{\alpha }{2}  increase and from the equation for margin of error we see the the critical  value varies directly with the margin of error , hence the margin of error  will increase also  

So  If the confidence level is increased, then the sample size would need to increase because a higher level of confidence increases the margin of error.

8 0
3 years ago
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