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3 years ago

Need help fast!!!! Pls to

Mathematics

2 answers:

skelet666 [1.2K]3 years ago

8 0

Here are the answers

Gala2k [10]3 years ago

6 0

Questions 1-6 are answered on here

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Help me pleaseee (you could just tell me the points or something)

Mrac [35]

Is this algebra one or two please mark me brainlist I need 1 more

3 0

3 years ago

The diameter of Jim’s circular flower bed is 10 feet. What is the area, in square feet, of Jim’s flower bed?

Setler79 [48]

The area of a circle is PiR^2
Divide 10 by 2, to get the radius.
Square the radius, 5, which gives you 25.
25Pi is your answer, which is C.)

8 0

4 years ago

Read 2 more answers

Three toed sloths move slowly using as littile energy as Possible.They sleep,Eat,and evening give birth upside down.A baby sloth

Bumek [7]

Answer:

3636 hours

Step-by-step explanation:

The calculation of duration of baby sloth sleep is shown below:-

A three-toes sloth usually sleeps is

= 101 hours per week.

Number of week is

= 36

Since we need to compute the duration of baby sloth's sleep so we need to multiply the number of weeks with number of hours per week

Therefore,

The duration of baby sloth's sleep in 36 weeks

= 36 x 101

= 3636 hours

5 0

3 years ago

Solve 5x - 8y = 11 for y.

disa [49]

Answer:

y = $\frac{5x-11}{8}$

Step-by-step explanation:

Given

5x - 8y = 11 ( subtract 5x from both sides )

- 8y = 11 - 5x ( multiply through by - 1 )

8y = - 11 + 5x = 5x - 11 ( divide both sides by 8 )

y = $\frac{5x-11}{8}$

3 0

3 years ago

Geometric Series assistance

Levart [38]

we have been asked to find the sum of the series

$\sum _{n=1}^5\left(\frac{1}{3}\right)^{n-1}$

As we know that a geometric series has a constant ratio "r" and it is defined as

$r=\frac{a_{n+1}}{a_n}=\frac{\left(\frac{1}{3}\right)^{\left(n+1\right)-1}}{\left(\frac{1}{3}\right)^{n-1}}=\frac{1}{3}$

The first term of the series is $a_1=\left(\frac{1}{3}\right)^{1-1}=1$

Geometric series sum formula is

$S_n=a_1\frac{1-r^n}{1-r}$

Plugin the values we get

$S_5=1\cdot \frac{1-\left(\frac{1}{3}\right)^5}{1-\frac{1}{3}}$

On simplification we get

$S_5=\frac{121}{81}$

Hence the sum of the given series is $\frac{121}{81}$

5 0

3 years ago