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3 years ago

The new cookie recipe has 1 1/2 cups of flour for every 1/2 cup of chocolate chips.

Mathematics

1 answer:

andre [41]3 years ago

4 0

Answer:

Step-by-step explanation:

1 1/2 cups for every 1/2 cup

im not exactly sure about the slope but i know the rate is 1:3

so i think they might be the same thing

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A company surveyed 1000 people on their age and the number of jeans purchased annually. The results of the poll are shown in the

Solnce55 [7]

Answer:

a) 0.437; b) 0.291

Step-by-step explanation:

For part a,

There are 280+210 = 490 people that are over 18 years old. Out of these, 119+95 = 214 purchase 2 pairs of jeans annually. This is

214/490 ≈ 0.437

For part b,

There are 87+69+74+11 = 241 people who purchase 3 or more pairs of jeans. There were a total of 220+290+280+210 = 1000 people; this means there were 759 people tho purchased fewer than 3 pairs of jeans.

Out of these, 21+74+126 = 221 were in the age group 12-18. This gives us

221/759 ≈ 0.291

8 0

3 years ago

HELP!!!!!<br> Solve:<br> -1/4 ÷ 2/3

katovenus [111]

3\12? R u in 6th? Cuz there's more that

7 0

3 years ago

Read 2 more answers

For the hypothesis test H0: μ = 10 against H1: μ >10 and variance known, calculate the Pvalue for each of the following test

Basile [38]

Answer:

a) $p_v =P(Z>2.05)=1-P(z$

b) $p_v =P(Z>-1.84)=1-P(z$

c) $p_v =P(Z>0.4)=1-P(z$

Step-by-step explanation:

Some previous concepts

The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct.

A z-test for one mean "is a hypothesis test that attempts to make a claim about the population mean(μ)".

The null hypothesis attempts "to show that no variation exists between variables or that a single variable is no different than its mean"

The alternative hypothesis "is the hypothesis used in hypothesis testing that is contrary to the null hypothesis"

Hypothesis

Null hypothesis: $\mu=10$

Alternative hypothesis: $\mu >10$

If the random variable is distributed like this: $X \sim N(\mu,\sigma)$

We assume that the variance is known so the correct test to apply here is the z test to compare means, the statistic is given by the following formula:

$z_o=\frac{\bar X -\mu}{\sigma}$

Since we have the values for the statistic already calculated we can calculate the p value using the following formulas:

Part a

$p_v =P(Z>2.05)=1-P(z$

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(2.05,0,1,TRUE)"

Part b

$p_v =P(Z>-1.84)=1-P(z$

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(-1.84,0,1,TRUE)"

Part c

$p_v =P(Z>0.4)=1-P(z$

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(0.4,0,1,TRUE)"

Conclusions

If we use a reference value for the significance, let's say $\alpha=0.05$ . For part a the $p_v$ so then we can reject the null hypothesis at this significance level.