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Dennis_Churaev [7]
3 years ago
9

PLEASE HELP WILL GIVE BRAINLIEST!!

Mathematics
1 answer:
ahrayia [7]3 years ago
8 0
They would be traveling at 47.5 mph
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Name a parallelogram that is neither a square, rhombus nor rectangle
Vedmedyk [2.9K]

With all due thinking...

I think a Diamond shape will befit your answer. So; The real answer is "Rhomboid"

The reason is that...

A rhomboid has four parallel sides. The opposite sides are equal, but the corners do not form right angles. Think of a rectangle that is slanted(a.k.a diamond) Thats what a Rhomboid is...

A parallelogram that dosent have equal sides is not a rhombus; and which dosent have Right angles are not rectangles and hence cannot be aquares either.

So in all Way a Rhomboid will mark the answer for your question.

Hope it helps..

Regards,

Leukonov/Olegion.

6 0
3 years ago
Read 2 more answers
Please help solve this problem
irina1246 [14]

Answer:

y = 15

Step-by-step explanation:

The triangles follow a scale factor. This scale factor can enlarge or make a triangle smaller, using this factor, like a ratio. We can do 22/10 to get this scale factor for the set, which is 2.2. Finally, divide 33 by 2.2 to get 15 for the missing side length y.

4 0
2 years ago
Mrs. Cho drives 45 miles in 1 hour. If her speed stays constant, how many hours will it take for her to drive 405 miles?
Novosadov [1.4K]
9 hours. 405/45=9 hours.
7 0
3 years ago
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Ted, the postman, has 110 letters to deliver. If Ted can deliver 10 letters in 5 minutes,
valina [46]

Answer:

55

Step-by-step explanation:

There are 11 tens in 110, so 11 times 5 is 55.

8 0
3 years ago
the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t
Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count Pr(A|B).

Use formula for conditional probability:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

1. The event A\cap B consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event A\cap B is

Pr(A\cap B)=\dfrac{1}{20}.

2. The event B consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event B is

Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.

3. Then

Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.

Answer: \dfrac{1}{2}.

5 0
3 years ago
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