Given :
A skyrocket is launched from a 8-foot-high platform with an initial speed of 220 feet per second.
The polynomial -16t² + 220t + 8 gives the height in feet that the skyrocket will rise in t seconds.
To Find :
How high will the rocket rise if it has a 7-second fuse?
Solution :
Since, it is given that the rocket has a fuse time of 7 seconds.
Putting value of 7 sec in given equation, we get :
Height = -16×( 7 )² + 220×( 7 ) + 8
Height = 764 m
Therefore, height of rocket in 7 second fuse is 764 m.
A + 4 = s
2(a+2) = (s+2)
plug in the upper equation into the lower equation
2(a+2) = (a+4+2)
2a+4 = a+6
a+4 = 6
a = 2 years old
Answer:
9x+18
Step-by-step explanation:
9 times x = 9x
9 times 2 = 18
they aren't compatable so you leave as is
40 x .05 = 2
40 + 2 = 42
$42 with sale tax
$2 total sales tax
