Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
A) 8 chocolate chip cookies
B) The ratio of sugar to oatmeal is 2:3 because there are 12 sugar and 18 oatmeal. 12/18 simplified is 2/3.
Sunscreen approx. 40.6 cents an oz
Lotion 6.4 cents an oz
( - 0.625, - 1.75 )
so since the first equation is already simplified , just replace it in the second equation
Answer:
112
Step-by-step explanation:
The general form of all percentage questions is: the chunk= (some percentage) (of the whole), or c=p*w
We know that 18% of students are 8th grade and that is 126 students, so p = 0.18 and c=126 (126 students are 18% of the whole school)
126 = (0.18)w, divide both sides by 0.18
126/(0.18) = w = 700
9th graders are 16% of the school or 16% of 700 students
c = (0.16) 700 = 112 students
