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MArishka [77]
3 years ago
12

Which ratio Best describes the relationship between the map distance in inches compared to the actual distance in miles?

Mathematics
1 answer:
Gnom [1K]3 years ago
5 0

Answer:

A. 7:1

Step-by-step explanation:

14/2 is 7

35/5 is 7

and 56/8 is 7

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13. You are going camping. The cost for renting a cabin at
statuscvo [17]

Answer:

The function is correct, I just don't see a question.

Step-by-step explanation:    6   21   6  10

C(n) = 12n + 65

I will make up a question.  How much will it cost 4 people each to rent the cabin?

C(n) = (12n + 65) / n         n = 4

      =  (12 × 4 + 65) / 4

      =  (48 + 65) / 4

      =     113 / 4

      =     $28.25

If your question is differnt just substitute the number of people into the question and solve for C(n)

7 0
3 years ago
What is the additive inverse of 3?<br> a. -3<br> b. a+(-a)=0<br> c. 0<br> d. -a
finlep [7]

Answer:

<em>A. -3</em>

Step-by-step explanation:

<em>3 and -3 are additive inverses since 3 + (-3) = 0. -3 is the additive inverse of 3.</em>

8 0
3 years ago
Read 2 more answers
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
If my original price is $60, then the sale price is $45, what is the percent discount
Scorpion4ik [409]
$60 -$45= $15

$15/ $60* 100%= 25%

The percent discount is 25%~
8 0
3 years ago
Can someone plz help me on 4-6
Anna [14]
The answer to 4-6 is negative 2
3 0
3 years ago
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