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3 years ago

Question 6

Mathematics

2 answers:

Brilliant_brown [7]3 years ago

6 0

Answer: 1st one

Step-by-step explanation:

mel-nik [20]3 years ago

3 0

Answer:

This is an example of positive nonlinear association

Step-by-step explanation:

So we know for a fact that the relationship between the the variables in the scatter plot is positive because its going up

The relationship is non linear because it has a curve

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Write an equation of the line that passes me that passes through (2,-5) and is parrallel to the line 2y=3x+10

Otrada [13]

Step-by-step explanation:

parallel means same slope/gradient

2y = 3x + 10

y = 1.5x + 5

let equation be y = 1.5x + b

sub (2, -5)

-5 = 1.5(2) + b

b = -8

therefore y = 1.5x - 8

Topic: Coordinate Geometry

If you like to venture further, feel free to check out my insta (learntionary). It would be best if you could give it a follow. I'll be constantly posting math tips and notes! Thanks!

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3 years ago

SOMEONE PLSS HELPPPPPPPP

garri49 [273]

Probability is 0/12 since there are no blue lollipops in the bag.

7 0

2 years ago

Read 2 more answers

A random sample of 500 registered voters in Phoenix is asked if they favor the use of oxygenated fuels year-round to reduce air

Stells [14]

Answer:

a) 0.0853

b) 0.0000

Step-by-step explanation:

Parameters given stated that;

H₀ : p = 0.6

H₁ : p = 0.6, this explains the acceptance region as;

p° ≤ $\frac{315}{500}$ =0.63 and the region region as p°>0.63 (where p° is known as the sample proportion)

a).

the probability of type I error if exactly 60% is calculated as :

∝ = P (Reject H₀ | H₀ is true)

= P (p°>0.63 | p=0.6)

where p° is represented as pI in the subsequent calculated steps below

= P $[\frac{p°-p}{\sqrt{\frac{p(1-p)}{n}}} >\frac{0.63-p}{\sqrt{\frac{p(1-p)}{n}}} |p=0.6]$

= P $[\frac{p°-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} >\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} ]$

= P $[Z>\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500} } } ]$

= P [Z > 1.37]

= 1 - P [Z ≤ 1.37]

= 1 - Ф (1.37)

= 1 - 0.914657 ( from Cumulative Standard Normal Distribution Table)

≅ 0.0853

The probability of Type II error β is stated as:

β = P (Accept H₀ | H₁ is true)

= P [p° ≤ 0.63 | p = 0.75]

where p° is represented as pI in the subsequent calculated steps below

= P $[\frac{p°-p} \sqrt{\frac{p(1-p)}{n} } }\leq \frac{0.63-p}{\sqrt{\frac{p(1-p)}{n} } } | p=0.75]$

= P $[\frac{p°-0.6} \sqrt{\frac{0.75(1-0.75)}{500} } }\leq \frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P $[Z\leq\frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P [Z ≤ -6.20]

= Ф (-6.20)

≅ 0.0000 (from Cumulative Standard Normal Distribution Table).

6 0

3 years ago

PLEASE HELP!!!!!! ILL GIVE BRAINLIEST *EXTRA 40 POINTS** !! DONT SKIP :((

Alecsey [184]

the answer is no. the solution is (1.333, 7.333)

4 0

3 years ago

Read 2 more answers

The ratio of vertical change to the horizontal change is called _________.

Nat2105 [25]

I think the ratio of a vertical change to the horizontal change is called slope.

7 0

3 years ago