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OLga [1]
3 years ago
7

An interface is a class that contains only the method headings and each method heading is terminated with a semicolon. True Fals

e
Computers and Technology
1 answer:
liubo4ka [24]3 years ago
3 0

Answer:

False

Explanation:

Interfaces are similar to classes in Java, but they are not a type of class. A class defines the attributes and behaviours of objects, while interface contains the methods that shows the behaviours to be implemented by a class.

A method is one or more group of statements, it does not need to end with a semicolon. Methods in interfaces are abstract and for a class to contain these abstract method, it must be defined in the class.

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In this chapter, you saw an example of how to write an algorithm that determines whether a number is even or odd. Write a progra
vagabundo [1.1K]

Answer:

// Program is written in Java Programming Language

// Comments are used for explanatory purpose

// Program starts here

public class RandomOddEve {

/** Main Method */

public static void main(String[] args) {

int[] nums = new int[100]; // Declare an array of 100 integers

// Store the counts of 100 random numbers

for (int i = 1; i <= 100; i++) {

nums[(int)(Math.random() * 10)]++;

}

int odd = 0, even = 0; // declare even and odd variables to 0, respectively

// Both variables will serve a counters

// Check for odd and even numbers

for(int I = 0; I<100; I++)

{

if (nums[I]%2 == 0) {// Even number.

even++;

}

else // Odd number.

{

odd++;

}

}

//.Print Results

System.out.print("Odd number = "+odd);

System.out.print("Even number = "+even);

}

8 0
4 years ago
Read 2 more answers
Create a flowchart that assigns a counselor to a student.
Nataly [62]
Please Help! Unit 6: Lesson 1 - Coding Activity 2
Instructions: Hemachandra numbers (more commonly known as Fibonacci numbers) are found by starting with two numbers then finding the next number by adding the previous two numbers together. The most common starting numbers are 0 and 1 giving the numbers 0, 1, 1, 2, 3, 5...
The main method from this class contains code which is intended to fill an array of length 10 with these Hemachandra numbers, then print the value of the number in the array at the index entered by the user. For example if the user inputs 3 then the program should output 2, while if the user inputs 6 then the program should output 8. Debug this code so it works as intended.

The Code Given:

import java.util.Scanner;

public class U6_L1_Activity_Two{
public static void main(String[] args){
int[h] = new int[10];
0 = h[0];
1 = h[1];
h[2] = h[0] + h[1];
h[3] = h[1] + h[2];
h[4] = h[2] + h[3];
h[5] = h[3] + h[4];
h[6] = h[4] + h[5];
h[7] = h[5] + h[6];
h[8] = h[6] + h[7]
h[9] = h[7] + h[8];
h[10] = h[8] + h[9];
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
if (i >= 0 && i < 10)
System.out.println(h(i));
}
}
4 0
3 years ago
Read 2 more answers
The laws governing search and seizure in the public sector are much more straightforward than those in the private sector. TRUE
Lapatulllka [165]

Answer:

True

Explanation:

Because of the contract that you have agreed to when joining the work force. Which is different from the private sector.

7 0
3 years ago
Jim maintains attendance records for his employees for the year. Row B includes the dates of attendance, and column A includes t
ahrayia [7]
To lock multiple rows (starting with row 1), select the row below the last row you want frozen, choose the View tab, and then click Freeze Panes. To lock multiple columns, select the column to the right of the last column you want frozen, choose the View tab, and then click Freeze Panes<span>.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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4 0
4 years ago
Read 2 more answers
Write a class with a constructor that accepts a String object as its argument. The class should have a method that returns the n
mote1985 [20]

Answer:

import java.util.Scanner;

public class VowelsAndConsonantsDemo {

   /**

   The printMenu methods displays a menu to the user

    */

   public static void printMenu() {

       System.out.println("Please select an option: ");

       System.out.println();

       System.out.print("a. Count the number of vowels in the string.\n"

               + "b. Count the number of consonants in the string.\n"

               + "c. Count both the vowels and consonants in the string.\n"

               + "d. Enter another string.\n"

               + "e. Exit the program\n");

   }

   public static void main(String[] args) {

       String input;      // to hold the user's input

       String option;     // to hold the user's input

       char choice;       // to hold a single character

       char exit;         // user chooses 'e' to exit the program

       char letter;       //the Y or N from the user's decision to exit

       // create a Scanner object to read keyboard input.

       //  Scanner keyboard = new Scanner(System.in);

       Scanner keyboard;

       do {

           keyboard = new Scanner(System.in);

           // ask user to enter string

           System.out.print("Enter a string: ");

           input = keyboard.nextLine();

           input = input.toLowerCase();

           System.out.println();

           printMenu();

           option = keyboard.nextLine();

           choice = option.charAt(0);

           VowelsAndConsonants words = new VowelsAndConsonants(input);

           switch (choice) {

               case 'a':

               case 'A':

                   System.out.println("Number of Vowels: " + words.getVowels());

                   break;

               case 'b':

               case 'B':

                   System.out.println("Number of Consonants: " + words.getConsonants());

                   break;

               case 'c':

               case 'C':

                   System.out.println("Number of Vowels & Consonants: " + words.getConsonants()

                           + words.getVowels());

                   break;

               case 'd':

               case 'D':

                   System.out.println("Enter a string: ");

                   break;

               case 'e':

               case 'E':

                   System.exit(0);

                   break;

               default:

                   System.out.println("You did not enter a valid choice.");

           }

           //

           // keyboard.nextLine();    //consumes the new line character after the choice

           // String answer = keyboard.nextLine();

           // letter = answer.charAt(0);

       } while (true);

   }

}

4 0
3 years ago
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