Suppose that a 64MB system memory is built from 64 1MB RAM chips. How many address lines are needed to select one of the memory
1 answer:
Answer:
6 address lines
Explanation:
The computation of the number of address lines needed is shown below:
Given that
Total memory = 64MB
=
=
Also we know that in 1MB RAM the number of chips is 6
So, the number of address lines is i..e 26 address lines
And, the size of one chip is equivalent to 1 MB i.e.
For a single 1MB chips of RAM, the number of address lines is
Therefore 6 address lines needed
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Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:
If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:
⇒ t = 8.7*10⁻⁴ sec.