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3 years ago

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Mathematics

1 answer:

Alecsey [184]3 years ago

4 0

Answers:

R = -3
S = -3
T = -9

For each row, you're adding the values of 'a' and 'b'. The first row has 1+2 = 3.

When adding two negatives, add the positive versions of each number, then make the result negative. So -1 + (-2) can be thought of as 1+2 = 3, then you make everything negative.

When adding a negative to a positive, you'll subtract the positive version of each number. The final result is positive if the larger absolute value is positive, or otherwise it's negative. We have -4+1 that can be thought of as 4-1 = 3, but since the '4' is larger and it is negative, this means -4+1 = -3.

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Answer:

Given :

ABC is a right triangle in which ∠ABC = 90°,

Also, Legs AB and CB are extended past point B to points D and E,

Such that,

$\angle EAC = \angle ACD = 90^{\circ}$

To prove :

$EB\times BD=AB\times BC$

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Now, In triangles ADC and CBD,

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For 2nd Solution: $y_2(t)=cosht$

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Step-by-step explanation:

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First order derivative:

$y'_1(t)=e^t$

2nd order Derivative:

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Put Them in equation y''-y=0

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In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

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First order derivative:

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