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spin [16.1K]
3 years ago
10

Which statement is true about the end behavior of the graphed function? The graph and choices are attached.

Mathematics
2 answers:
nadezda [96]3 years ago
7 0

The correct answer is A) as the x values go to positive infinity, then the graph goes to negative infinity.

We can tell this by looking at the graph values as x goes up. You'll notice, as we get higher and higher, the graph disappears down. This means it is heading towards negative infinity for the rest of the graph.

Kamila [148]3 years ago
4 0
<h2>Answer:</h2>

The statement  which is true about the end behavior of the graphed function is:

  • As the x-value goes to positive infinity , the function's value go to minus infinity.      
<h2>Step-by-step explanation:</h2>

We know that the end behavior of the function is the value where it approaches when x tends to plus infinity and minus infinity.

 From the graph of the function we see that the graph first decreases continuously and then it increases and again it decreases to minus infinity.

Also,

when x → -∞ we see that  f(x) → ∞

and when  x → ∞ then f(x) → -∞

As the function has opposite behavior in both the directions this means that the function is odd.

At x=0 the value of function is: -2

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Evaluate the variable expression when a=-4, b=2, c=-3, and d =4. b-3a/bc^2-d​
gtnhenbr [62]

Answer:

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

\dfrac{b-3a}{bc^{2}-d}=1

Step-by-step explanation:

Evaluate:

\dfrac{b-3a}{bc^{2}-d}

When a=-4, b=2, c=-3, and d =4

Solution:

Substitute, a=-4, b=2, c=-3, and d =4 in above expression we get

\dfrac{b-3a}{bc^{2}-d}=\dfrac{2-3(-4)}{2(-3)^{2}-4}\\\\=\dfrac{2+12}{18-4}\\\\

\dfrac{b-3a}{bc^{2}-d}=\dfrac{14}{14}=1

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

\dfrac{b-3a}{bc^{2}-d}=1

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3 years ago
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3 years ago
Farmer Ed has 9,500 meters of fencing,
Andreas93 [3]

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get:</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: </em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for x</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equation</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distribute</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y</em>

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<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y You can see that this is a parabola which opens down, meaning that the point of maximum area will be at the vertex, y = </em><em>- </em><em>b</em><em>/2a = -7500/[2(-2)] = 1875</em>

<em>/2a = -7500/[2(-2)] = 1875 </em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750</em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 </em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2</em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2 </em>

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3 years ago
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Savatey [412]

Answer:

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Step-by-step explanation:

X-6= -22

X = -22+6

X = - 16

6 0
2 years ago
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